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Snowcat [4.5K]
2 years ago
10

Solve the function. h(x)= 6x - 10 ————- X + 3 Help please

Mathematics
1 answer:
Rus_ich [418]2 years ago
8 0

Answer:

X+3=0

X=-3

H(x)=6*-3 - 10

H(x) =-18 - 10

H(x) =-28

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Whats the slope to this. <br><br> Giving brainliest. Correct answer
klasskru [66]

Answer:

m=-25

Step-by-step explanation:

m=Δh/Δt

(Im choosing for the difference in height and time (Δh and Δt) to be the difference between the data in the first two rows)

m=(4500-5000)/(20-0)

m=-500/20

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8 0
3 years ago
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Zari folds the net shown into model of a solid figure. How many edges, faces, and vertices does the model have?
adoni [48]

Answer:

Faces = 6

Vertices = 8

Edges = 12

Step-by-step explanation:

In a solid geometric shape :

         A face is a flat surface : faces = 6

         A vertex (plural: vertices) is a Corner : vertices = 8

         An edge is a particular type of line segment joining

                                                          two vertices : Edges = 12

                       

6 0
2 years ago
Write the equation (in point-slope form) for the line parallel to y = x + 4 and passes
Tanya [424]

Answer:

y = x-7

Step-by-step explanation:

<u>Step 1:  Write the equation in point-slope form</u>

Point Slope Form:  y-y_{1}=m\left(x-x_{1}\right)

<u>Plug in the numbers and solve</u>

<u />y - (-2) = 1(x - 5)

y + 2 = x - 5

y + 2 - 2 = x - 5 - 2

y = x-7

Answer:  y = x-7

8 0
2 years ago
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Which expression is equivalent to square root 55x^7y6/11x^11y^8
Novay_Z [31]

Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

6 0
2 years ago
the length of the rectangle is 2 less than 3 times the width. The perimeter is 12. Find the length and the width.
In-s [12.5K]

width=2
length= 4

explanation in the attached picture
5 0
2 years ago
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