2/-3 *n+7/3
-2n/3+7/3
-2n/3 +3*7/3/3
-2n+3*7/3/3
-2n+7/3
So A
Answer:
y = x + 6
Step-by-step explanation:
y = x + b
when x = 0, y = 6. so....
6 = (0) + b
6 = b
so, y = x + 6
(4x2 – 4x – 7)(x + 3)
(4x2 – 4x – 7)(x) + (4x2 – 4x – 7)(3)
4x2(x) – 4x(x) – 7(x) + 4x2(3) – 4x(3) – 7(3)
4x3 – 4x2 – 7x + 12x2 – 12x – 21
4x3 – 4x2 + 12x2 – 7x – 12x – 21
4x3 + 8x2 – 19x – 21
Answer:
The outer diameter of the shaft to 2s.f is 12.65cm
Step-by-step explanation:
We know that the expression for the area of a circular cross section is
A=
given data
area of cross section=
bore diameter d= 8cm
from the area of cross section we can solve for the outer diameter D
solving for D we have
Put the values where the variables are, then do the arithmetic.
8 - 8/2 +7² = 8 - 4 + 49 = 53