<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%201%7D%7B2x%20-%201%7D%20%20-%20%20%5Cfrac%7Bx%20-%201%7D%7B2x%20%2B%201%

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3 years ago

7D%20%20%3D%200" id="TexFormula1" title=" \frac{x + 1}{2x - 1} - \frac{x - 1}{2x + 1} = 0" alt=" \frac{x + 1}{2x - 1} - \frac{x - 1}{2x + 1} = 0" align="absmiddle" class="latex-formula">

I need some help

Mathematics

1 answer:

lubasha [3.4K]3 years ago

8 0

x=0

because you must

determine the undefined range

write all numerators above the common denomonator

multiply the parenthesis

collect the alike terms

remove parenthesis

eliminate the opposites collect the like terms

set the numerator equal to 0

divide both sides by 6

check if thesolution is the defined range

if so then you would find your answer X=0

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3 years ago

One fourth the sum of x and ten is identical to x minus 4."

Lynna [10]

Answer and Step-by-step explanation:

We are given the word format of an equation.

Let's right it out in numerical form.

$\frac{1}{4} (x + 10) = x - 4$

The first part says One fourth the sum of x and 10

The sum of x and 10 would be shown as x + 10, and one fourth of that means that $\frac{1}{4}$ is multiplying (x + 10).

In this case, identical would mean equal to.

So, $\frac{1}{4}$ (x + 10) would be = to something.

It says that it is identical to x minus 4 (x - 4).

$\frac{1}{4} (x + 10) = x - 4$ is the equation.

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3 years ago

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Step-by-step explanation:

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3 years ago

Solve by factoring:

DerKrebs [107]

A.(x+3)(x+4)=0
x=-3,-4
B.X=5,4
hope this helps

7 0

3 years ago

Read 2 more answers