7D%20%20%3D%200" id="TexFormula1" title=" \frac{x + 1}{2x - 1} - \frac{x - 1}{2x + 1} = 0" alt=" \frac{x + 1}{2x - 1} - \frac{x - 1}{2x + 1} = 0" align="absmiddle" class="latex-formula">
I need some help
1 answer:
x=0
because you must
determine the undefined range
write all numerators above the common denomonator
multiply the parenthesis
collect the alike terms
remove parenthesis
eliminate the opposites collect the like terms
set the numerator equal to 0
divide both sides by 6
check if thesolution is the defined range
if so then you would find your answer X=0
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45|3
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1
Answer:
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Step-by-step explanation:
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ANSWER
No solution
EXPLANATION
The first equation is
and the second equation is
We equate the two equations to obtain;
This implies that
There is no real number whose square is -1.
Therefore, the equation has no solution.
Answer: 32 and 42
Step-by-step explanation:
5j +12
j= 4
j = 6
5(4) + 12
5 times 4 = 20
20 + 12 = 32
5(6) + 12
5 times 6 = 30
30 + 12 = 42
3x - 4 = <span>3(-3) - 4 = -9 - 4 = -13
</span>3x - 4 = <span>3(-1.4) - 4 = -4.2 - 4 = -8.2
answer
range { -13, -8.2}</span>
