(3x - 4)(2x^2 + 2x - 1) = 3x(2x^2 + 2x - 1) - 4(2x^2 + 2x - 1) = (6x^3 + 6x^2 - 3x) - (8x^2 + 8x - 4) = 6x^3 + 6x^2 - 3x - 8x^2 - 8x + 4 = 6x^3 - 2x^2 - 11x + 4
Answer:
T=98W-115W+1840
Step-by-step explanation:
$98 per credit at Westside (W)
$115 per credit at Pinewood (P)
Expression 1 : 98W+115P=T
Expression 2 : W+P=16
Combined: if W=16-P
Total=98W+115(16-W)
T=98W-115W+1840
If there are 20 groups of 10, then there are 200 pencils. Subtract 200 and 137 to get the number of dull pencils.
Ok so your original equation was y=4(x-2)²-1
Therefore we need to expand the bracket to find the original equation.
To do this we need to find (x-2)²=x²-4x+4
Now we multiply this by 4 and subtract 1
4x²-16x+15 Therefore B is the answer
Cups = c
Plates = p
6p + 5c = 23.80 ==> multiply by 6 ==> 36p + 30c = 142.80
7p + 6c = 28.00 ==> multiply by 5 ==> 35p + 30c = 140.00
Now use algebra to have the 30c be on one side and the rest on the other:
36p + 30c = 142.80 | -36p
30c = 142.80 - 36p
35p + 30c = 140.00 | -35p
30c = 140.00 - 35p
Now set them equal to each other about the 30c:
142.80 - 36p = 140.00 - 35p
Use algebra to solve for p:
142.80 - 36p = 140.00 - 35p | +36p
142.80 = 140.00 + p | - 140
2.80 = p
Go back to one of the "30c" equations and plug in the value for p:
30c = 140 - 35p
30c = 140 - 35(2.80)
30c = 140 - 98
30c = 42 | /30
c = 42/30
c = 1.4
Plates are $2.80
Cups are $1.40
