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cluponka [151]
3 years ago
7

The sandbox is in the shape of a right rectangular prism. The area of the base of the sandbox is 124.8 square centimeters, and i

t will have a height of 5.7 centimeters. Mr. Berger plans to fill the sandbox half full of sand. What is the volume of sand he will need to fill half of the sandbox?
Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer: he will need 355.68 centimeters³ of sand to fill half of the sandbox

Step-by-step explanation:

The formula for determining the volume of a rectangular prism is expressed as

Volume = length × base × height

It can also be expressed as

Volume = base area × height

The area of the base of the sandbox is 124.8 square centimeters, and it will have a height of 5.7 centimeters. This means that the volume of the sandbox is

124.8 × 5.7 = 711.36 centimeters³

Since Mr. Berger plans to fill the sandbox half full of sand, the volume of sand he will need to fill half of the sandbox is

711.36/2 = 355.68 centimeters³

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6 less than twice a number is at least 15. Write an inequality and solve.
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Answer:

2a-6>=15 this is because the key word at least means it can be 15 or higher but it cannot be less than 15.

Step-by-step explanation:

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3 years ago
The temperature in the afternoon was 10 degrees. By 8 pm, the temperature was -5
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Answer:

The temperature had dropped by 15 degrees (-15 if you don't want it positive.)

Step-by-step explanation:

Okay!

This is a subtraction problem.

If it started off at 10, and went down to -5, we can do |-5 - 10| (I am using the two bars because it said change.) And we get 15!

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3 years ago
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A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish
Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or \frac{x}{y}=\frac{333}{444}

⇒ \frac{x}{y}=\frac{3}{4}

⇒ y = \frac{4x}{3} --------(1)

Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}

\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0
3 years ago
Is the answer I chose correct?
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Yes it is good luck too you
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Answer:

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