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4 years ago

What is the ph of a solution with [h ] = 1.25x10–10 m?

Chemistry

2 answers:

MissTica4 years ago

4 0

Ph= - log[H+] = - log[1.25 x 10^-10] = 9.9. Hope it helps

ira [324]4 years ago

4 0

Answer:

pH= 9.9 This pH is alkaline

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH can be measured in an aqueous solution using a numerical value scale that measures the acidic solutions (highest concentration of hydrogen ions) and the alkaline solutions (base, lowest concentration) of the substances.

The numerical scale that measures the pH of substances ranges from 0 to 14. The most acidic substances approach number 0, and the most alkaline (or basic) substances that approach number 14. And a pH value of 7 is neutral; This means that the substance or solution is neither acidic nor alkaline.

The pH is expressed as the negative logarithm (base 10) of the concentration of hydronium ions [H₃O⁺] or hydrogen ions [H⁺]. This is:

pH= -log₁₀ [H₃O+]= -log₁₀ [H⁺]

also expressed as

pH= -log [H₃O+]= -log [H⁺]

So, in this case, you know that [H⁺]=1.25*10⁻¹⁰ M

Replacing in the definition of pH:

pH= -log 1.25*10⁻¹⁰

You get:

pH= 9.9

pH is alkaline

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Varvara68 [4.7K]

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3 years ago

What volume of 2.0 M HCl in mL will neutralize 25.0 mL of 1.00 M KOH?

MakcuM [25]

CaVa=CbVb
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V=12.5ML

3 0

3 years ago

A solution of citric acid (H₃C₆H₅O₇) with a known concentration of 0.200 M H₃C₆H₅O₇ is titrated with a 0.750 M NaOH solution. Ho

Anestetic [448]

The quantity of NaOH required to reach the third equivalence point is 20mL.

Using the titration formula,

CaVa/CbVb = Na/Nb

Where,

Ca = concentration of citric acid (0.200 M)

Cb = concentration of NaOH (0.750 M)

Va = Volume of citric acid (25.0 mL)

Vb = volume of NaOH (x mL)

Na = number of reacting mole of citric acid (3)

Nb = number of reacting mole of NaOH (1)

Therefore Vb ( x mL) =CaVaNb/CbNa

= 0.2× 25×3/0.75 ×1

= 15/0.75

Vb ( x mL) = 20 mL

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brainly.com/question/23631409

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3 years ago

A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235

trapecia [35]

Answer : The value of $\Delta E$ of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

$\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}$

Molar mass of helium = 4 g/mole

$\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole$

Now we have to calculate the heat.

Formula used :

$q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)$

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

$c_p$ = specific heat of helium = 20.8 J/mol.K

$T_1$ = initial temperature = 310.0 K

$T_2$ = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

$q=nc_p(T_2-T_1)$

$q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K$

$q=-19.5J$

Now we have top calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 1.21 L

$V_2$ = final volume = 0.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (0.99-1.21)L$

$w=0.22L.artm=0.22\times 101.3J=22.29J$

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the value of $\Delta E$ of the gas.

$\Delta E=q+w$

$\Delta E=(-19.5J)+22.29J$

$\Delta E=2.79J$

Therefore, the value of $\Delta E$ of the gas is 2.79 Joules.

3 0

3 years ago

What happens to an ionic compound when it is dissolved in water?

damaskus [11]

Answer:

Explanation:

because the ion are Mobil which mean they are free not combined and carry a charge but when they are combined/ fixed in position they can't carry a charge so therefore can't conduct electricity :)

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