Question

2. Match the shapes given to their correct areas.

Answer 1

Applying the formula for each identified shape that are given, the correct areas to each shape are:

a. Square = 134.6 sq. yd

b. Circle = 452.2 sq. cm

c. Parallelogram = 40.6 sq. cm

d. Rectangle = 43.2 sq. ft

e. Trapezium = 25.7 sq. m

f. Triangle = 21.6 sq. ft

a. The shape given is a square.

Area of the square = $s^2$

Where,

s = 11.6 yd

Plug in the value of s

Area of the square = $11.6^2 = 134.6 yd^2$

b. The shape given is a circle.

Area of the circle = $\pi r^2$

• Where,

r = 12 cm

• Plug in the value of r

Area of the square = $\pi \times 12^2 = 452.2 cm^2$

c. The shape given is a parallelogram.

Area of the parallelogram = $bh$

• Where,

b = 7 cm

h = 5.8 cm

• Plug in the value of b and h

Area of the parallelogram = $7 \times 5.8 = 40.6 cm^2$

d. The shape given is a rectangle.

Area of the rectangle = $l \times w$

• Where,

l = 8.3 ft

w = 5.2 ft

• Plug in the value of l and w

Area of the rectangle = $8.3 \times 5.2 = 43.2 ft^2$

e. The shape given is a trapezium.

Area of the trapezium = $\frac{1}{2} (a + b) \times h$

• Where,

a = 2.8 m

b = 10.4 m

h = 3.9 m

• Plug in the value of a, b, and h

Area of the trapezium = $\frac{1}{2}(2.8 + 10.4) \times 3.9 = 25.7 m^2$

f. The shape given is a triangle. (See attachment for the shape).

Area of the triangle = $\frac{1}{2} \times b \times h$

• Where,

b = 9 ft

h = 4.8 ft

• Plug in the value of b, and h

Area of the triangle = $\frac{1}{2} \times 9 \times 4.8 = 21.6 ft^2$

Therefore, applying the formula for each identified shape that are given, the correct areas to each shape are:

a. Square = 134.6 sq. yd

b. Circle = 452.2 sq. cm

c. Parallelogram = 40.6 sq. cm

d. Rectangle = 43.2 sq. ft

e. Trapezium = 25.7 sq. m

f. Triangle = 21.6 sq. ft

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