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Ierofanga [76]
2 years ago
15

2. Match the shapes given to their correct areas.

Mathematics
1 answer:
aliina [53]2 years ago
5 0

Applying the formula for each identified shape that are given, the correct areas to each shape are:

a. <em>Square </em>= 134.6 sq. yd

b. <em>Circle </em>= 452.2 sq. cm

c. <em>Parallelogram </em>= 40.6 sq. cm

d. <em>Rectangle </em>= 43.2 sq. ft

e. <em>Trapezium </em>= 25.7 sq. m

f. <em>Triangle</em> = 21.6 sq. ft

a. The shape given is a square.

Area of the square = s^2

Where,

s = 11.6 yd

Plug in the value of s

Area of the square = 11.6^2 = 134.6 $ yd^2

b. The shape given is a circle.

Area of the circle = \pi r^2

  • Where,

r = 12 cm

  • Plug in the value of r

Area of the square = \pi \times 12^2 = 452.2 $ cm^2

c. The shape given is a parallelogram.

Area of the parallelogram = bh

  • Where,

b = 7 cm

h = 5.8 cm

  • Plug in the value of b and h

Area of the parallelogram = 7 \times 5.8 = 40.6 $ cm^2

d. The shape given is a rectangle.

Area of the rectangle = l \times w

  • Where,

l = 8.3 ft

w = 5.2 ft

  • Plug in the value of l and w

Area of the rectangle = 8.3 \times 5.2 = 43.2 $ ft^2

e. The shape given is a trapezium.

Area of the trapezium = \frac{1}{2} (a + b)  \times h

  • Where,

a = 2.8 m

b = 10.4 m

h = 3.9 m

  • Plug in the value of a, b, and h

Area of the trapezium = \frac{1}{2}(2.8 + 10.4) \times 3.9 = 25.7 $ m^2

f. The shape given is a triangle. <em>(See attachment for the shape).</em>

Area of the triangle = \frac{1}{2}  \times b  \times h

  • Where,

b = 9 ft

h = 4.8 ft

  • Plug in the value of b, and h

Area of the triangle = \frac{1}{2} \times 9 \times 4.8 = 21.6 $ ft^2

Therefore, applying the formula for each identified shape that are given, the correct areas to each shape are:

a. <em>Square </em>= 134.6 sq. yd

b. <em>Circle </em>= 452.2 sq. cm

c. <em>Parallelogram </em>= 40.6 sq. cm

d. <em>Rectangle </em>= 43.2 sq. ft

e. <em>Trapezium </em>= 25.7 sq. m

f. <em>Triangle</em> = 21.6 sq. ft

Learn more here:

brainly.com/question/22560863

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