Answer:
377 choices
Step-by-step explanation:
From the above question, we are told that
A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses.
Let us represent each choice by :
A = Appetizer = 6
M = Main meal = 8
D = Dessert = 5
a) The combination of the 3 choices together
AMD=6 × 8 × 5=240
b) AM= Appetizer and Main meal
= 6 × 8 = 48
c) AD= Appetizer and Dessert
= 6 × 5 = 30
d) MD = Main meal × Dessert
= 8 × 5 = 40
e) A,M,D (each alone)=
Appetizer + Main meal + Dessert
= 6 + 8 + 5
= 19
Assuming all choices are available, how many different possible meals does the restaurant offer?
This is calculated as:
AMD + AM + AD + MD + A,M,D
240 + 48 + 30 + 40 + 19
= 377 choices
Answer:
The number is -1/2.
Step-by-step explanation:
I am assuming they are fractions. So we have the equation:
5/2 x + 2/3 = -7/12
We multiply through by 12 to eliminate the fractions:
5/2 * 12 x + 2/3 * 12 = -7/12 * 12
30x + 8 = -7
30x = -15
x = -15/30
x = -1/2.
Answer:
I cant
Step-by-step explanation:
Im sorry
Answer:
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Step-by-step explanation:
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