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3 years ago

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Cody Summer sells tires for tractor trailers. He earns 4.5% commission on the first $6,000 in sales, 8% commission on the next $

6,000, and 12% commission on sales over $12,000. Last month he sold $18,000 worth of tires. What was his total commission?

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

The Answer is $1,470.

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Find a 95% confidence interval for the mean auditory response time for subjects with a visual response time of 200 ms. The 95% c

Sveta_85 [38]

Answer:

hello your question is incomplete attached below is the complete question

answer : ( 184.019 , 206.219 )

Step-by-step explanation:

The 95% confidence interval for the mean auditory response time for subjects with a visual response time of 200 ms can be calculated using this relationship below

y = Bo + B1 ( 200 ) = 195.118621 , sy =

hence a 95% confidence interval = 195.118621 ± 2.306( 4.813492) i.e. ( 184.019 , 206.219 )

attached below is the remaining part the solution

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3 years ago

Liza decides to bake a cake .If she use 3/4 cups of flour to make the first cake and 1/2 cup of flour for her second cake.How ma

Natalka [10]

Answer:

5/4 cups of flour

Step-by-step explanation:

3/4+1/2 = 1 1/4 or 5/4

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3 years ago

Read 2 more answers

About what percent of men aged 25 to 34 are less than 70 inches tall

Fantom [35]

Are there no answer choices?

7 0

4 years ago

Read 2 more answers

Brainliest will be given to the correct answer!

IrinaK [193]

Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for $b_{1}$ . $b_{1} = \frac{2\cdot A}{h}-b_{2}$

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from $b_{1}$ and $b_{2}$ to $b$ . $b = \frac{A}{h}$

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

$A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2})$ (Eq. 1)

Where:

$h$ - Height of the trapezoid, measured in centimeters.

$b_{1}$ , $b_{2}$ - Lengths fo the bases, measured in centimeters.

$A$ - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})$ Definition of division.

3) $2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}]$ Compatibility with multiplication/Commutative and associative properties.

4) $h = \frac{2\cdot A}{b_{1}+b_{2}}$ Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that $A = 91\,cm^{2}$ , $b_{1} = 16\,cm$ and $b_{2} = 12\,cm$ , then height of the trapezoid is:

$h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}$

$h = 6.5\,cm$

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for $b_{1}$ :

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})$ Definition of division.

3) $2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2})$ Compatibility with multiplication/Commutative and associative properties.

4) $2\cdot A \cdot h^{-1} = b_{1}+b_{2}$ Existence of multiplicative inverse/Modulative property

5) $\frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1}$ Definition of division/Compatibility with addition/Commutative and associative properties

6) $b_{1} = \frac{2\cdot A}{h}-b_{2}$ Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for $b_{1}$ .

C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: ( $A= 215\,cm^{2}$ , $h = 8.6\,cm$ and $b_{2} = 30\,cm$ )

$b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm$

$b_{1} = 20\,cm$

The length of the other base of the trapezoid is 20 centimeters.

D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from $b_{1}$ and $b_{2}$ to $b$ . Now we present the procedure to clear $b$ below:

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $b_{1} = b_{2}$ Given.

3) $A = \frac{1}{2}\cdot h \cdot (2\cdot b)$ 2) in 1)

4) $A = 2^{-1}\cdot h\cdot (2\cdot b)$ Definition of division.

5) $A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b$ Commutative and associative properties/Compatibility with multiplication.

6) $b = A \cdot h^{-1}$ Existence of multiplicative inverse/Modulative property.

7) $b = \frac{A}{h}$ Definition of division/Result.

8 0

4 years ago

Town B is 40 km due north of town a what is the bearing of a from B

Dafna11 [192]

Answer:

180°

Step-by-step explanation:

In bearing the protractor is placed in the North-South direction(eastside) thus directly north is on a bearing of 0°.After you mark the point B. A will be directly south which is on a bearing of 180°

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4 years ago