Answer:
Options (B), (C) and (E) are the correct options.
Step-by-step explanation:
Equation that represents relation between the number of cars c and the number of vans v to transport 80 students is,
4c + 6v = 80
Option A.
If c = 12,
4(12) + 6(v) = 80
48 + 6v = 80
6v = 32
Which is not equal to 2.
Therefore, Option A is incorrect.
Option B
If c = 14,
4(14) + 6(v) = 80
56 + 6v = 80
6v = 24
v = 4
Therefore, c = 14 and v = 4 is a pair of solutions.
Option B is correct.
Option C.
If c = 6 and v = 11
4(6) + 6(11) = 24 + 66
= 90
This means with 6 cars and 11 vans 90 students can be transported. Therefore, there will be extra space.
Option C is correct.
Option D.
If c = 10 and v = 8
4(10) + 6(8) = 40 + 48
= 88
Therefore, 10 cars and 8 vans are enough to transport 80 students.
So option D is incorrect.
Option E.
If c = 20,
4(20) + 6(v) = 80
80 + 6v = 80
v = 0
Therefore, for 20 cars go no vans are needed.
Option E is correct.
Option F.
Constraints in this situation,
Minimum number of cars to be used = 20
c ≥ 20
Minimum number of vans to be used = ≈ 14
v ≥ 14
Therefore, Option (F) is incorrect.
It depends whether the ones place is 5 or up. If it is you would round up. For example 36 would round to 40.
Now if it is less than 4 you would round down, for example 33 would be rounded to 30.
26.46/8.4 = $3.15 per gasoline
Answer:
The range of the function are the values of height which are from 3, 4, 5, ..., 50
Step-by-step explanation:
The given parameters are;
The height at which the ball is caught = 5 feet
The height at which the ball was hit = 3 feet
The maximum height reached by the ball = 50 feet
The height of the ball given as a function of time is f(t) s = u·t - 1/2·g·t²
Where;
s = 50 feet
g = 9.81 m/s²
Therefore, we have;
50 = u·t - 1/2 × 9.81 × t²
50 = u·t - 4.905 × t²
Therefore, the range are obtainable values for f(t) which range from 3 to 50.
Yes she will have have money to buy all the toppings