Answer:
Step-by-step explanation:
From the given information,
Considering both cases when p = 0.5 and when p ≠ 0.5
the probability that the gambler will quit an overall winner is:
where ;
N.k = n and k = m
Hence, the probability changes to:
is p ≠ 0.5 and k/N =
is P = 0.5
Perimeter is when you add up all the sides of a shape. For Anthony's shape, it would be 6 time 5, or 30 inches. For Carol's shape, it would be 6 times 5, or 30. Both shapes have the same perimeter. Hopefully this helps, let me know if you have any more questions.
Answer:
1. 4x^2 + 12x= 4x(x+3)
2. 6x^2 + 24x= 6x(x+4)
3. 8x^2 - 16x= 8x(x−2)
4.8x^2 + 12x= 4x(2x+3)
5. 9x^2 + 3x= 3x(3x+1)
6. 21x+7x^2= 7x(3+x)
7. 5x^2 +45x= 5x(x+9)
8. 25x-5x^2 = 5x(5-x)
1. 16x^2 +12x= 4x(4x+3)
2. 24x^2 +42x= 6x(4x+7)
3. 16x^2- 24x= 8x(2x-3)
4. 8x^2 + 18x= 2x(4x+9)
5. 9x^2 + 21x= 3x(3x+7)
6. 28x + 35x^2= 7x(4+5x)
7. 30x^2+ 45x= 15x(2x+3)
8. 20x- 36x^2= 4x(5-9x)
1. 5x^2y +10xy= 5xy(x+2)
2. 12xy^2 +18xy= 6xy(2y+3)
3.15xy-10x= 5x(3y-2)
4. 60x-25x^2y= 5x(12-5xy)
5. 21x^2y- 49xy= 7xy(3x-7)
6. 24xy^2 -42xy= 6xy(4y-7)
7. 30x^2y^2 - 15xy= 15xy(2xy-1)
8. 8xy^2 - 32x^2y= 8xy(y-4x)
PS: Hope this helps!! Have an Amazing Day!!
Answer:
Step-by-step explanation:
a) amplitude is the answer
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Answer:
The taylor's series for f(x) = ln x centered at c = 1 is:
![ln (x) = \sum\limits^{\infty}_{n = 1} {\frac{(-1)^{n+1}(x-1)^n}{n} }](https://tex.z-dn.net/?f=ln%20%28x%29%20%3D%20%5Csum%5Climits%5E%7B%5Cinfty%7D_%7Bn%20%3D%201%7D%20%7B%5Cfrac%7B%28-1%29%5E%7Bn%2B1%7D%28x-1%29%5En%7D%7Bn%7D%20%7D)
Step-by-step explanation:
The calculations are handwritten for clarity and easiness of expression.
However, the following steps were taken in arriving at the result:
1) Write the general formula for Taylor series expansion
2) Since the function is centered at c = 1, find f(1)
3) Get up to four derivatives of f(x) (i.e. f'(x), f''(x), f'''(x),
)
4) Find the values of these derivatives at x =1
5) Substitute all these values into the general Taylor series formula
6) The resulting equation is the Taylor series
![ln (x) = \sum\limits^{\infty}_{n = 1} {\frac{(-1)^{n+1}(x-1)^n}{n} }](https://tex.z-dn.net/?f=ln%20%28x%29%20%3D%20%5Csum%5Climits%5E%7B%5Cinfty%7D_%7Bn%20%3D%201%7D%20%7B%5Cfrac%7B%28-1%29%5E%7Bn%2B1%7D%28x-1%29%5En%7D%7Bn%7D%20%7D)