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Area = length x width
x² + 12x = l * x
A.
First, you factor x from x² + 12x
area = x (x+12)
area = (x+12) * x
Length = x + 12
B.
If x = 10,
l = x + 12 = 10 +12 = 22
length = 22
and
Area = x² + 12x = 10² + 12(10) = 100 + 120 = 220
area = 220
Hope this helps :)
x² + 12x = l * x
A.
First, you factor x from x² + 12x
area = x (x+12)
area = (x+12) * x
Length = x + 12
B.
If x = 10,
l = x + 12 = 10 +12 = 22
length = 22
and
Area = x² + 12x = 10² + 12(10) = 100 + 120 = 220
area = 220
Hope this helps :)
<span>Given that RS = 6, ST = 3, and SL = 4, to find NS, we first find QS.
Notice that NQS forms a right triangle with the right andle at Q.
To find QS, we notice that QRS forms a right triangle with the right angle at R.
Note that ST = QR = 3 and RS = 6.
Using pythagoras theorem
Note that NQ = SL = 4.
Using pythagoras theorem
</span>
Notice that NQS forms a right triangle with the right andle at Q.
To find QS, we notice that QRS forms a right triangle with the right angle at R.
Note that ST = QR = 3 and RS = 6.
Using pythagoras theorem
Note that NQ = SL = 4.
Using pythagoras theorem