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zavuch27 [327]
3 years ago
9

Find the perimeter and area of the polygon shown below.

Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

I'm sorry. I cannot explicitly give you an answer. The picture of the polygon is not provided. You may have forgotten to upload it, nevertheless, I''ll try my best to be of help to you.

Step-by-step explanation:

There are many different polygons. But the general formula to finding the perimeter of a polygon is:

P = n * l

n = number of sides

l= value shared and assigned to each side

The general formula to finding the area of a regular polygon is:

A = (n*l*apothem )/2

n = number of sides

l = length of one side

apothem = the value of the segment connecting the center of the polygon to a midpoint of one of the sides.

Hope this helps a little! You can always submit the question again with the picture and I'll be more than happy to help you. <3

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Copy DEF to the line so that S is the vertex. This task will be complete when you have constructed an angle with vertex S that i
tino4ka555 [31]

Explanation:

There are numerous videos and web sites that can show you the process of copying an angle. Some are animated. The best we can do here is show you a diagram with instructions. Of course, your curriculum materials already provide that.

__

1. Set the compass to a convenient radius. Use that to draw an arc through rays ED and EF, using point E as the center.

2. Without changing the compass setting, draw a similar arc using S as the center, making sure it crosses the line containing S and extends far enough to accommodate the following steps. (In the attached, we show a full circle, because the tool we used won't draw an arc with a specific radius.)

3. Mark the points where the arc crosses ED as G, and where it crosses EF as H. Mark the point where the arc crosses the line containing S as I.

4. Set the compass radius to the distance GH. Using I as the center draw an arc with that radius so that it crosses the one made in step 2. Call that intersection point J. (Again, we have shown a circle because of the limitations of the tool being used for our diagram.)

5. Draw ray SJ to complete the angle copy.

4 0
3 years ago
Micah is flying a kite and has used all of the 50 meters of the string. If the kite is 13 meters above the ground, what is the a
Norma-Jean [14]

Answer:

60.0735651 degrees

Step-by-step explanation:

So the hypotenuse is 50 and the vertical leg is 13

For the angle, you need to find the sine (opposite and hypotenuse)

sin(x) = 13/50

x = asin(13/50)

x = 60.0735651

4 0
3 years ago
An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in t
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Answer: decreases, 2.65 atm

Step-by-step explanation: it’s explained on edg.

4 0
4 years ago
Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
Construct the 95% confidence interval for the population mean using the appropriate distributions. a. A random sample of 50 peop
SSSSS [86.1K]

Answer: 95% confidence interval would be (26.01,29.39).

Step-by-step explanation:

Since we have given that

n = 50

Mean = 27.7

Standard deviation = 6.12

We need to construct 95% confidence interval for the population.

so, z = 1.96

So, it becomes,

\bar{x}\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=27.7\pm 1.96\times \dfrac{6.12}{\sqrt{50}}\\\\=27.7 \pm 1.69\\\\=(27.7-1.69,27.7+1.69)\\\\=(26.01,29.39)

Hence, 95% confidence interval would be (26.01,29.39).

4 0
4 years ago
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