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aev [14]
3 years ago
11

Justify x over 3 minus 7 equals 11

Mathematics
1 answer:
drek231 [11]3 years ago
4 0

Answer:

54/3-7=11

Step-by-step explanation:

x/3<u>-7=11</u>

   +7 +7

(3)x/3=18(3)

     x=54

Check

54/3-7=11

18-7=11

11=11

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4% of what days is 56 days
leva [86]
The answer would be 14 because 4x__=56 ? 4 x14 =56
6 0
3 years ago
-2 -13.8x = -8 -(6x+1)
Varvara68 [4.7K]
-2 -13.8x = -8 -6x -1
First, I distributed the negative 1 that was outside of the parentheses to the positive 6x and the positive 1.

-2 -13.8x = -9 -6x
Then I added the negative 8 to the negative 1 which equals negative 9.

-2 -13.8x +6x = -9 -6x +6x
After that I used the addition property and added a positive 6x to both sides.

-2 -7.8x = -9
Then simplifying.

+2 -2 -7.8x = -9 +2
After simplifying, I used the addition property again, adding a positive 2 to both sides.

-7.8x = -7
Simplified.

-7.8x (-1) = -7 (-1)
Then I multiplied both sides by with a negative 1 since the variable cannot be a negative.

7.8x = 7
Simplified

(1/7.8) 7.8x = (1/7.8) 7
Then, to isolate the veriable, I multiplied 1/7.8 to both sides.

x = 1.11428571429
The answer !

I hope this helped !
7 0
3 years ago
May I have help to figure out how to do this? It is confusing! :(
RSB [31]

Answer:

it should be 80%

Step-by-step explanation:

I hope this helps

3 0
2 years ago
How do you answer <br> #5.
avanturin [10]
Umm this might be wrong, but i think you have do the inverse, which would make -4 positive, then add that to the 2, and then subtract that from 0.6  and then whatever you answer you get is equal to the variable z.
5 0
3 years ago
Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used
ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0
3 years ago
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