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lubasha [3.4K]
4 years ago
12

The rectangle below has an area of x^2-25 square meters and a length of x+5.

Mathematics
1 answer:
Archy [21]4 years ago
7 0

Answer:

(x-5)

Step-by-step explanation:

factor the equation and the sign is x-5 because the equation has to be negative at the 25.

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PLEASE HELP ME WITH THE LITTLE QUESTION
vlada-n [284]

Answer:

y = -x +2

Step-by-step explanation:

First let's find the slope.

(-1,3) and (4,-2)

3 - -2/ -1 - 4 = 5/-5 = -1

Slope = -1

Now let's use slope intercept form:

y1-y2=m(x1-x2)

Let's plug in our slope for m.

y1-y2= -1 (x1-x2)

And now let's substitute y2 and x2 for one of our points, I'll use (4,-2)

y1+2 = -1(x1- 4)

y= -x + 4 -2

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3 years ago
What is the slope for (20,8) and (4,4)
Yuki888 [10]

Answer:

m=\frac{1}{4}

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3 years ago
The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.
stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(5-(-3))^2+(8-2)^2}

AB=\sqrt{(8)^2+(6)^2}

AB=\sqrt{64+36}

AB=\sqrt{100}

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Similarly,

BC=\sqrt{(11-5)^2+(0-8)^2}

BC=\sqrt{(6)^2+(8)^2}

BC=\sqrt{36+64}

BC=\sqrt{100}

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And,

AC=\sqrt{(11-(-3))^2+(0-2)^2}

AC=\sqrt{(14)^2+(-2)^2}

AC=\sqrt{196+4}

AC=\sqrt{200}

AC=10\sqrt{2}

Two sides of the triangle are equal, i.e., AB=BC. So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

AB^2+BC^2=10^2+10^2

AB^2+BC^2=100+100

AB^2+BC^2=200

AB^2+BC^2=AC^2

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0
3 years ago
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iogann1982 [59]

Answer:

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Step-by-step explanation:

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Your friends pay rate per 8 hours is $72.

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