3 years ago

Find all natural numbers n such that 1+3+5+7+...+(2n-1) sum is divisible by 4

Mathematics

2 answers:

Ierofanga [76]3 years ago

6 0

n ∈ natural even numbers

Step-by-step explanation:

1 + 3 + 5 + 7 + … + (2n-1)

a = 1
b = 2
Uₙ = 2n - 1

sum of the first n terms :

Sₙ = n/2(a + Uₙ)

Sₙ = n/2(1 + 2n - 1)

Sₙ = n/2(2n)

Sₙ = n²

∴ so, the solution of n is all natural even numbers

aev [14]3 years ago

3 0

Refer to the attachment

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