2 years ago

Could someone please tell me how to solve this?

1 answer:

6 0

You would take the CUBED ROOT of 125 instead of the square root, this will help find your answer..
It’s 5, because 5^3 is 125

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noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

4 years ago

puteri [66]

multiply by 24

eg: 2 days = 2×24 = 48hrs

7 0

2 years ago

Vladimir79 [104]

Answer:

3 and 1

Step-by-step explanation:

4 0

3 years ago

Deffense [45]

Answer:

My guess is 195.

Step-by-step explanation:

225 + 120 = 345 - 150 = 195

8 0

3 years ago

bagirrra123 [75]

I think that it might be 5... ? I'm not sure though don't blame me if its wrong.

4 0

3 years ago