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Darya [45]
3 years ago
9

Using language c, find the nth Fibonacci, knowing that nth Fibonacci is calculated by the following formula: - If n = 1 Or n = 2

then F(n) = 1 - If n>2 then F(n) = F(n-1) + F(n-2)
Computers and Technology
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:

#include <stdio.h>

int fib(int n) {

 if (n <= 0) {

   return 0;

 }

 if (n <= 2) {

   return 1;

 }

 return fib(n-1) + fib(n-2);

}

int main(void) {

 for(int nr=0; nr<=20; nr++)

   printf("Fibonacci %d is %d\n", nr, fib(nr) );

 return 0;

}

Explanation:

The code is a literal translation of the definition using a recursive function.

The recursive function is not per se a very efficient one.

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Democrat good luck dude
5 0
3 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
3 years ago
A network administrator is planning redundant devices and cabling in a switched network to support high availability. Which bene
a_sh-v [17]

Answer:

Redundant paths can be available without causing logical Layer 2 loops.

Explanation:

  • Spanning Tree Protocol is used to allow redundancy in the Layer 2 switched networks without creating cycles/circles also called loops.
  • These loops are called physical loops.
  • When two parts of the switched network are connected via two or more Layer 2 switches this result in a loop.
  • This affects the performance of the network as the result of broadcast packets flooding.
  • STP puts one port of the switch to forward mode and the rest of the ports within the same part of the network to the blocking mode to avoid broadcast packet flooding. STP puts all the ports that are allowing redundant paths to block mode and the one port that is left after this is placed in forward mode.
  • Spanning Tree Algorithm is used by STP to determine the optimal path  of switch to the network.
  • Bridge Protocol Data Units are used to share the information about the optimal path determined by the spanning tree algorithm with other switches.
  • This information helps STP to eliminate the redundant paths.
  • So this is how STP tracks all the links in the switched network and eliminates redundant loops by allowing only one active path to the destination while blocking all other paths.
7 0
3 years ago
For an activity with more than one immediate predecessor activity, which of the following is used to compute its earliest finish
laila [671]

Answer:

The correct option is A

Explanation:

In project management, earliest finish time for activity A refers to the earliest start time for succeeding activities such as B and C to start.

Assume that activities A and B comes before C, the earliest finish time for C can be arrived at by computing the earliest start-finish (critical path) of the activity with the largest EF.

That is, if two activities (A and B) come before activity C, one can estimate how long it's going to take to complete activity C if ones knows how long activity B will take (being the activity with the largest earliest finish time).

Cheers!

7 0
3 years ago
Why is there more than one Brainly website?
marta [7]

they are for different countries and languages

8 0
3 years ago
Read 2 more answers
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