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3 years ago

Subtract 8x + 2 from 4x – 6

Mathematics

1 answer:

Fantom [35]3 years ago

7 0

Answer:

-4x-8

Step-by-step explanation:

First, set them up as (4x-6) - (8x +2).

Then simplify.

4x-6-8x-2

4x-8x-6-2

-4x-8

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Consider the circle below. B (7w - 4)º A C (5w + 20) D Determine mAB.

Lady bird [3.3K]

Answer: d

Step-by-step explanation:

4 0

3 years ago

In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website

expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

$\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42$

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

$s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772$

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is $n = 10$

The significance level is $\alpha = 1 - 0.05 = 0.95$

The estimate, which is the sample standard deviation, is of $s = 0.8772$ .

Now, we have to find the critical values for the Pearson distribution. They are:

$\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228$

$\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004$

The confidence interval for the population variance is:

$\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}$

$\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}$

$0.3641 < \sigma^2 < 2.5646$

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

$\sqrt{0.3641} = 0.6034$

$\sqrt{2.5646} = 1.6014$

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0

3 years ago

The measure of ∠A is 6° greater than the measure of ∠B. The two angles are complementary. Find the measure of each angle.

zhenek [66]

Lines and angles

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5 0

4 years ago

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A cylinder has a diameter of 16 cm and a volume of 804.247cm2. What is the height of the cylinder?

serg [7]

Answer:

The height is 4cm

Step-by-Step Explanation:

Use the formula:

V= π (d/2)² h

Solve for h

h=(V/π(d/2)²

804.25/(π (16/2)²

4cm

Hope this helps :)

7 0

3 years ago

Read 2 more answers

How to solve an equation

Mama L [17]

Simplify each side of the equation by removing parentheses and combining like terms.

Use addition or subtraction to isolate the variable term on one side of the equation.

Use multiplication or division to solve for the variable.

8 0

2 years ago