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3 years ago

10

Subtract 8x + 2 from 4x – 6

1 answer:

Fantom [35]3 years ago

7 0

Answer:

-4x-8

Step-by-step explanation:

First, set them up as (4x-6) - (8x +2).

Then simplify.

4x-6-8x-2

4x-8x-6-2

-4x-8

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What is the simplest form of the ratio 32 : 48?

podryga [215]

The reduced form of
32
48
is
2
3

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator
GCD of 32 and 48 is 16
Divide both the numerator and denominator by the GCD
32 ÷ 16
48 ÷ 16
Reduced fraction: 2/3

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Sarika’s house is 5 km from her office. She covered 4 ½ by train and the remaining by walk.

givi [52]

Answer:

1/2 km or 0.5 km

Step-by-step explanation:

In the attached file

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4 years ago

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Evaluate (8 + t) to the power of three minus 6 when t equals 2

UkoKoshka [18]

Answer:

994

Step-by-step explanation:

First, let's translate the statement into a mathematical expression.

$(8+t)^3-6$

Now, we can evaluate the expression when t = 2.

$(8+2)^3-6$
$(10)^3-6$
$1000-6$
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2 years ago

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Can u help solve these questions please

Tasya [4]

Answer:

Step-by-step explanation:

$\sqrt[4]{(16a^4)^5}=(16a^4)^{\frac{5}{4}}$ [Since, $\sqrt[n]{x}=x^{\frac{1}{n}}$ ]

$=(16)^{\frac{5}{4}}(a^4)^{\frac{5}{4}}$

$=(2^4)^{\frac{5}{4}}(a^4)^{\frac{5}{4} }$

$=(2^{4\times \frac{5}{4}})(a^{4\times \frac{5}{4}})$

$=2^5a^5$

$\sqrt[5]{(b^{\frac{1}{4}})^6}=\sqrt[5]{b^{\frac{6}{4}}}$

$=\sqrt[5]{b^{\frac{3}{2}}}$

$=(b^{\frac{3}{2}})^{\frac{1}{5} }$

$=b^{\frac{3}{10}}$

$\sqrt[3]{\frac{c^{15}}{c^9}}=\sqrt[3]{c^{15-9}}$

$=(c^6)^{\frac{1}{3}}$

$=c^{6\times \frac{1}{3} }$

= c²

$\sqrt[4]{16d^6\times 16d^{-5}}=\sqrt[4]{(2)^4(d^{6-5})(2)^4}$

$=\sqrt[4]{2^{(4+4)}d}$

$=\sqrt[4]{(2^8)d}$

$=2^{\frac{8}{4}}d^{\frac{1}{4}}$

$=2^2d^{\frac{1}{4}}$

$=4d^{\frac{1}{4}}$

8 0

3 years ago