All categories

2 years ago

What is the slope of the line that contains the points (–5, 6) and (14, –7)?

1 answer:

8 0

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -5 &,& 6~) 
% (c,d)
&&(~ 14 &,& -7~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-7-6}{14-(-5)}\implies \cfrac{-7-6}{14+5}\implies \cfrac{-13}{19}$

You might be interested in

What 100-38 (656) =1000000

Likurg_2 [28]

100 - 38(656) = 1000000

100 - 24928 = 1000000

-24828 = 1000000

This is false!

Hope this helps! ;)

4 0

2 years ago

A high school football pennant is in the shape of an isosceles triangle. The base is 18 inches long. The sides meet at an angle

Oksanka [162]

Answer:

The length of each side is 26.3 cm

Step-by-step explanation:

Opposite sides of an isoceles triangle are equal

The isoceles triangle is divided into 2 right-angled triangles so the length of one side can be calculated using trigonometric ratio

When the isoceles triangle is divided, the angle in the right-angled triangle is 20° (1/2 of 40°) and the base is 9cm (1/2 of 18 cm), the hypotenuse side is calculated using trigonometric ratio

Let the length of the hypotenuse side be y

9/y = sin 20°

y = 9/0.3420 = 26.3

Length of each side is 26.3 cm

3 0

2 years ago

Suppose the area of a circle is 49π. What is its radius

pentagon [3]

The radius is 7 what it is telling you is that you already did the square 4^2*3.14=49 pi.

4 0

2 years ago

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations.

Nostrana [21]

$x^3-27i=0$
$x^3=27i$
$x^3=27e^{i\pi/2}$
$x=\left(27e^{i\pi/2}\right)^{1/3}$
$x=3e^{i(\pi/2+2\pi k)/3}$
$x=3e^{i\pi(4k+1)/6}$

where $k\in\{0,1,2\}$ . This means you have

$x=3e^{i\pi/6}=\dfrac32(\sqrt3+i)$
$x=3e^{i5\pi/6}=\dfrac32(-\sqrt3+i)$
$x=3e^{i9\pi/6}=-3i$

as the solutions to the original equation.

4 0

2 years ago

Use the diagram of the right triangle above and round your answer to the nearest hundredth. If m <br> a. 17.32 m<br> b. 6.93 m<b

zepelin [54]

In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m

7 0

2 years ago