What is the slope of the line that contains the points (–5, 6) and (14, –7)?

1 answer:

8 0

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -5 &,& 6~) 
% (c,d)
&&(~ 14 &,& -7~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-7-6}{14-(-5)}\implies \cfrac{-7-6}{14+5}\implies \cfrac{-13}{19}$

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Answer:

Step-by-step explanation:

1. The coefficient of 2 $x^{2}$ is 2. Therefore, the answer is 2 for a. 1 is the coefficient of -x after we add it to the left side. Therefore, b is 1. C is 5, as it is the only whole number.