The total number of games a girl play against a boy is 25, the number of games a girl plays against a boy is 10, the fraction of the games are boy-versus-boy is 2/9, and 1/5 is the fraction of all games at the tournament Anita plays.
<h3>How to carry out Permutation and Combination?</h3>
We are given that there are 5 girls and 5 boys in a chess club.
Thus, total games that girls play against a boy = 5×5 = 25
The number of games a girl play against another is the total number of games = 10
The number of games that are boy vs boy = 10
The number of games Boy vs Boy + Girl vs Girl + Boy vs Girl = 10 + 10 + 25 = 45
Fraction of the games that are boy vs boy = 10/45 = 2/9
If Anita is one of the club members, then Anita will have to play against 9 people at the tournament.
Total number of games = 45
Then the fraction of all games at the tournament Anita play the game.= 9/45 ⇒ 1/5
Thus, the total number of games a girl play against a boy is 25, the number of games a girl plays against a boy is 10, the fraction of the games are boy-versus-boy is 2/9, and 1/5 fraction of all games at the tournament Anita plays.
Read more about Permutation and Combination at; brainly.com/question/4658834
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