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hoa [83]
2 years ago
8

Which team is responsible for defending the network against attacks in a risk training scenario?

Computers and Technology
1 answer:
vagabundo [1.1K]2 years ago
6 0

Red teams are offensive security professionals who are experts in attacking systems and breaking into defenses. Blue teams are defensive security professionals responsible for maintaining internal network defenses against all cyber-attacks and threats.

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Which of the following does not accurately describe asynchronous communication?
worty [1.4K]

Answer:

A. While new media is dependent on whether users function in real-time or delayed mode, feedback is not as timely when communication is asynchronous.

Explanation:

Asynchronous communication can be defined as a data communication technique in which exchange of data between a sender and a recipient isn't in real time.

There's usually a time lag, meaning it doesn't require the recipient to respond immediately.

For example, responding to an email or text several hours later.

6 0
3 years ago
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The fundamental building block in every Hypertext Markup Language (HTML) document is the _____ tag, which marks a component in t
AVprozaik [17]

Answer:

<div></div>

Explanation:

The <div></div> tag allows you to build containers to the text that you want to include in your html

6 0
3 years ago
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Which of the following film pioneers helped make films widely available to ordinary people?
Verizon [17]
<span>Steven Spielberg, and or Paul Williams

</span>
6 0
2 years ago
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This program needs to be written in Java. Along with NO For/while loops, and no methods.
Umnica [9.8K]
The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.

Here is the starter code:

import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;

… (fill in other cases)


}
}
}

Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html

There might be a better way, but without loops or methods this is all I got.
6 0
2 years ago
Write a function PrintShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, pr
PSYCHO15rus [73]

// Writing a C++ function

void PrintShampooInstructions(int numCycles){

if(numCycles < 1) // if  condition stands

cout<< "To few";

else if(numCycles >4)

cour<<"Too Many";

else{

// looping the variable for desired out put

for(int i=0;i<numCycles;i++)

cout<<i<<":"<<" Lather and rinse."<<endl;

}

}

6 0
3 years ago
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