Write a function PrintShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, pr
int "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline. Example output with input 2: 1: Lather and rinse. 2: Lather and rinse. Done. Hint: Declare and use a loop variable.
2 answers:
Answer:
public static void printShampooInstructions(int numOfCycles){
if(numOfCycles < 1){
System.out.println("Too few.");
}
else if(numOfCycles > 4){
System.out.println("Too many.");
}
else {
for(int index = 0; index < numOfCycles; ++index){
System.out.println((index + 1) + ": Lather and rinse.");
}
System.out.println("Done.");
}
}
Explanation:
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Answer / Explanation:
Assuming we define the end points as ( x₁ , y₁) and (x₂ , y₂) and the rectangular window edge as ( Xmin ,Ymin and Xmax , Ymax)
The illustration of the above assumption is represented in the diagram below.
Now, suppose the line segment is between the points P₁ = ( x₁ , y₁) , and
P₂ = (x₂ , y₂).
We can then create a line recalling and using parametric form,
P(t) = ( 1 - t) P₁ + tP₂ , t ∈ {0 , 1 },
So, for the X axis, we have,
tₓ = P₁ₓ - x ÷ P₁ₓ - P₂ₓ
We need to note that at this point we need to know the minimum and maximum unclipped values for parameter t from each dimension.
Therefore,
- ( tmin , tmax ) = ( 0,1) means unclipped line
-tmin > tmax means completely clipped out line
– Some other range means partially clipped out line.
