Since the histogram is not symmetric, the grades shown in the math class below are not normally distributed.
<h3>When does a histogram represent a normal distribution?</h3>
A histogram represents a normal distribution if it symmetric.
In this problem, we have that:
- 57% of the grades are on the left tail.
- 25% of the grades are on the center.
- 18% are on the right tail.
Since the percentages at the tails are different, the histogram is not symmetric, and the grades shown in the math class below are not normally distributed.
More can be learned about the normal distribution at brainly.com/question/24537145
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The answer for this is 37.5. I can't show the work because i searched it up on Google.
Answer:
7) BC = 10
8) BD = 20
Step-by-step explanation:
7) The segment addition theorem tells you ...
AB +BC +CD = AD
(3x+2) +(2x+4) +(3x-2) = 28
8x +4 = 28 . . . . collect terms
8x = 24 . . . . . . . subtract 4
x = 3 . . . . . . . . . divide by 8
BC = 2x+4 = 2(3) +4
BC = 10
__
8) AB +BD = AC +CD
(2x -14) +(-7 +3x) = (2x -3) +(9)
5x -21 = 2x +6
3x = 27
x = 9
BD = -7 +3x = -7 +3(9)
BD = 20
Answer:
$420.69
Step-by-step explanation:
if you do some thinking, you'll easily find out the answer is $420.69
not only is it a funny number, it's also a NICE amount of cash i would really love to have. anyways, hope this helps!
P.S: i have all A's in school ;)
So here first you have to have same denominators to subtract and add.
to make same denominator you have to multiply something to them which meets up to their lowest common multiple (LCM). so here the easiest thing is multiply each denominator to the other but remember you have to multiply them to the numerator too.
3×9/5×9-2×5/9×5
so it becomes
27/45-10/45
17/45
as you cant bring to its simplest form since the answer in a prime no. leave it like that.
