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valkas [14]
3 years ago
11

Zachary travels on a journey of 50 miles. He spends half of

Mathematics
2 answers:
Mars2501 [29]3 years ago
7 0
I divided 50 miles by 2 = 25 miles (walked) 25 miles (horseback)
I divided 25 by 3 = 8.33
I divided 25 by 9 = 3
Added together = 8.33 + 3 = 11.33
So time to complete the journey 11.33 hour
swat323 years ago
3 0

50/2 = 25

Therefore he spent 25 miles on his horse and 25 miles walking

He covers 9 miles every hour on his horse

25/9 = 2 \frac{7}{9} hours

He covers 3 miles every hour walking

25/3 = 8 \frac{1}{3} hours

Total time taken to complete his journey = 2 \frac{7}{9} + 8 \frac{1}{3} = 11 \frac{1}{9} hours

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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
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\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

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-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

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