All categories

3 years ago

Can someone help me? 3 2/5 - 1 4/5=?

Mathematics

1 answer:

ioda3 years ago

7 0

17/5-9/5 —> 17-9/5 ——> 8/5 (FINAL ANSWER)

You might be interested in

Why does Malvolio want to believe that "All is Fortune"? Malvolio knows that everything is determined by fate, so he's going to

sattari [20]

He wants to believe that he can change his circumstances by being in the right place at the right time.

8 0

3 years ago

Read 2 more answers

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

3 years ago

Help me with my review please

Greeley [361]

Answer:

GHF = EDF

Step-by-step explanation:

Those two tringles are the only even triangles.

4 0

3 years ago

HELP

Firdavs [7]

Answer:

4-4=0

16-6-10=0

17-3-4-10=0

1-2+1=0

Step-by-step explanation:

4 0

3 years ago

Heeeelllpppssss pleeaassee.....…………

Kay [80]

Answer:

x= -8 x=2

Step-by-step explanation:

x^2 +6x - 6 = 10

Subtract 10 from each side

x^2 +6x -16 =0

Factor what 2 numbers multiply to -16 and add to 6

8*-2 = -16

8-2 = 6

(x+8) (x-2) =0

Using the zero product property

x+8 =0 x-2 =0

x= -8 x=2

8 0

3 years ago

Can someone help me? 3 2/5 - 1 4/5=?​

Can someone help me? 3 2/5 - 1 4/5=?