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KonstantinChe [14]
2 years ago
11

For the polynomial, list each real zero and its multiplicity. Determine whether the graph

Mathematics
2 answers:
avanturin [10]2 years ago
7 0
Mxkdjdjdndkfkdjdkdndkd
SVEN [57.7K]2 years ago
6 0

Answer:

A, B, F

Step-by-step explanation:

took the test

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John is a runner what is the speed if you Ran<br> hundred metter sprint in 10 seconds
Ahat [919]

Answer:

1000

Step-by-step explanation:

3 0
3 years ago
Evaluate the expression 34 ÷ (14 − 5) × 2.
bonufazy [111]

Answer:

68/9

Step-by-step explanation:

34 ÷ (14 − 5) × 2

PEMDAS

Parentheses first

34 ÷ (9) × 2

We have no Exponents so

Multiply and Divide from left to right

34/9 *2

68/9

5 0
2 years ago
Read 2 more answers
Can someone please help me with this question
Tanzania [10]

Answer:

B) [1, 4, 7]

Step-by-step explanation:

Substitute 0 in

f(0) = 3(0) + 1

Multiple

f(0) = 0 + 1

f(0) = 1

Substitute 1 in

f(1) = 3(1) + 1

f(1) = 3 + 1

f(1) = 4

Substitute 2 in

f(2) = 3(2) + 1

2 = 6 + 1

f(2) = 7

8 0
2 years ago
Read 2 more answers
A scuba diver starts at 85 3/4 meters below the surface of the water and descends until he reaches 103 1/5
RSB [31]

Answer:

From his starting point of 85 3/4, he descended 17 9/20 meters

Step-by-step explanation:

We want to know how much farther he went down from his starting point.

103 1/5 - 85 3/4

S

tart off by making the denominators of both the numbers the same.

103 1/5 - 85 3/4

103 4/20 - 85 15/20

Make them into improper fractions

2064/20 - 1715/20 = 349/20

Make 349/20 into a mixed fraction

17 9/20

5 0
3 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
3 years ago
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