Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
I am doing this on apex aswell and i am stuck for the last few ones. I know that the answer to #1 is: Natalie- SAS and Emma- SSS the other ones im not so sure about. sorry for the lack of help, just thought one answer is better than none lol
We can solve this problem by dividing 9/12 by 2/12. We should do this because to find how many sets of something are in a number, the question is asking us to do division. Doing this, we get 9/12 * 12/2, giving us our answer of 4.5 sets of 2/12 in 9/12.
<h2>2 units down</h2><h2>1 unit to the left</h2>
What is ur subject i would lov o help
