Answer:
1.) 113500J
2.) 237m
Explanation:
Hello!
To solve this exercise follow the following steps, the description and complete process is in the attached image
1. Draw the full sketch of the problem.
2. The work is defined as the product of the trajectory by the force that is parallel to this direction, for this reason to find the work done we multiply the horizontal distance (250m) by the applied force (454N)
3. The potential energy is equal to the product of mass, gravity and height and is equal to the work done by the force applied by the cyclist, of this relationship and using algebra we can find the height that the cyclist climbed
4. We use the sine function to find the diagonal distance using the height and angle of the slope
Because of the opposing forces on the car like friction because there is no more acceleration
A is only the area of one tile. It wants the area of the whole floor.
area of parallelogram is b*h=0.952. There are 9500 of them so 0.952*9500=904.4 (answer c)
Answer:
V=11.74m/s, 69.59°
Explanation:
From newtons equation of motion ,we know that
V^2 = u^2+2gh
for the rt
For the vertical component of the speed
Vy^2=V0^2+ 2gh
Vy= the final speed in the vertical axis
V0= initial speed, 0m/s
g= acceleration due to gravity 9.81m/s
h=height/distance between the eagle and the lake
Vy^2= 2*9.81*6.2
Vy =√121.644
Vy=11.02m/s
The resultant speed will be
V=(Vy^2+Vx^2)^0.5
V=(11.02^2+4.1^2)^0.5
V=137.7241^0.5
V=11.74m/s
Direction
Tan^-1(11.02/4.1)
β=69.59°
V=11.74m/s, 69.59°
Answer =11.74m/s, b°
Explanation:
The X-component of the velocity = Vcosx. Where, V = magnitude of the velocity. The x component of velocity will depend on the diagram. It the angle is measured from the x-axis which is considered the horizontal then Vx = Vcos(theta). The magnitudes of the components of velocity v → are v x = v cos θ and v y = v sin θ , v x = v cos θ and v y = v sin θ , where v is the magnitude of the velocity and θ is its direction relative to the horizontal, as shown in Figure 4.12. Derivation of the Trajectory Formula.
y = refers to the vertical position of the object in meters. x = refers to the horizontal position of the object in meters. Horizontal velocity component: Vx = V * cos(α)
Vertical velocity component: Vy = V * sin(α)
Time of flight: t = [Vy + √(Vy² + 2 * g * h)] / g.
Range of the projectile: R = Vx * [Vy + √(Vy² + 2 * g * h)] / g.
Maximum height: hmax = h + Vy² / (2 * g)
