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grin007 [14]
4 years ago
5

What property of objects is best measured by their capacitance?

Physics
1 answer:
vekshin14 years ago
3 0
<h2>Answer: the object's ability to store charge</h2>

Explanation:

The capacitance C is defined as the relationship between the electric charge of each conductor and the potential difference between them. That is, it is the capacity of a device to store electrical charge.  

In other words:  

It is the property that bodies have to maintain an electric charge.  

Mathematically it is defined as:  

C=\frac{Q}{V}  

where:  

C is the capacitance value of a capacitor. Its unit is Farad F; named in honor of the physicist Michael Faraday  

Q is the electric charge of the conductor, measured in coulombs C.  

Vis the electric potential to which the conductor is located, measured in Volt.  

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Ship A is located 4.2 km north and 2.7 km east of ship B. Ship A has a velocity of 22 km/h toward the south and ship B has a vel
kotykmax [81]

Answer:

(a) The x-component of velocity is 31.55 km/h

(b) The y-component of velocity is 44.92 km/hr

Solution:

As per the solution:

The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.

Velocity of ship A, \vec{u_{A}} = 22 km/h towards South = - 22\hat{j}

Velocity of ship B, \vec{u_{B}} = 39 km/h Towards North east at an angle of 36^{\circ} = \vec{u_{B}} = 39sin36^{\circ} \hat{j}

Now, the velocity of ship A relative to ship B:

\vec{u_{AB}} = \vec{u_{A}} - \vec{u_{B}}

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\vec{u_{B}} = 39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}

Now,

\vec{u_{AB}} = - 22\hat{j} +39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}

\vec{u_{AB}} = 31.55\hat{i} - 44.92\hat{j}

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