Explanation:
The relative velocity is the velocity of the athlete relative to the ground plus the velocity of the javelin relative to the athlete.
v = 4.2 m/s + 10.3 m/s
v = 14.5 m/s
<span>To determine the magnitude and the direction of the resultant force, we assume that the forces are in XY coordinate plane and the angles that are given are from the x axis.
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<span>The 110 N force is said to act at 90 deg which means it is along the Y axis. The </span><span>55 N force is said to act at 0 deg which means it is along the X axis. so, a right angle is made by the two forces. Thus, the
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<span>X component of the resultant force = 55 N </span>
<span>Y component of the resultant force = 110 N </span>
<span>Magnitude of the resultant force would be calculated as follows:
R = √(Fx^2 + Fy^2)
R = √(55^2 + 110^2) </span>
<span>R = √(15125) </span>
<span>R = 123 N </span>
<span>The resultant force would have its terminal side in the x-axis. We calculate angle θ as follows:
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<span>tan θ = Fy/Fx </span>
<span>tan θ = 110 N /55 N = 2
</span>θ = arctan(2)
θ <span>= 63.4 degrees
</span>Therefore, the m<span>agnitude of the resultant force is 123 N and the direction would be at an angle of 63.4 degrees.</span>