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Tems11 [23]
3 years ago
15

Help me answer number 9 PLEASEEEE

Mathematics
1 answer:
katrin [286]3 years ago
5 0
BD = BA + AD

51 = 26 + AD

-26 on both sides

AD = 25
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Identify the zeros of f(x) = (x + 1)(x − 8)(5x + 2). (5 points)
Sergeeva-Olga [200]

Answer:

Set equal to zero and solve for  x . The multiplicity of a root is the number of times the root appears.

x = − 1  (Multiplicity of  1 )

x = 8  (Multiplicity of  1 )

x = − 2 5  (Multiplicity of  1 )

Step-by-step explanation:

3 0
2 years ago
#7:Write the expression in simplest<br> radical form.<br> V24x5y2
vazorg [7]

2x^2y√6x


the image has the answer in a mor clear form


8 0
3 years ago
The local amusement park was interested in the average wait time at their most popular roller coaster at the peak park time (2 p
Effectus [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

118, 124, 108, 116, 99, 125, 138, 118, 119, 121, 65, 130, 120

Ordered data:

65, 99, 108, 116, 118, 118, 119, 120, 121, 124, 125, 130, 138

1.)

90th percentile :

0.9(n + 1)th term

n = sample size = 13

0.9(14) th term

= 12.6th term

= (12 + 13)th / 2

= (130 + 138) / 2

= 134

Third quartile (Q3) = 75th percentile

0.75(n + 1)th term

n = sample size = 13

0.75(14) th term

= 10.5th term

= (10 + 11)th / 2

= (124 + 125) / 2

= 124.5

What is the first quartile?

First quartile (Q1) :

0.25(n + 1)th term

n = sample size = 13

0.25(14) th term

= 3.5th term

= (3 + 4)th / 2

= (108 + 116) / 2

= 112

(4) What is the 10th percentile?

0.1(n + 1)th term

n = sample size = 13

0.1(14) th term

= 1.4th term

= (1 + 2)th / 2

= (65 + 99) / 2

= 82

(5) 65tb percentile :

0.65(n + 1)th term

n = sample size = 13

0.65(14) th term

= 9.1th term

= (9 + 10)th / 2

= (121 + 124) / 2)

= 122.5

(6) What is the IQR?

Q3 - Q1

124.5 - 112

= 12.5

(7) What are the lower and upper limits?

Maximum = 138

Minimum = 65

4 0
2 years ago
Multiplying binomials<br> Determine the product<br> (x-3) (x-8)
MrMuchimi
X^2-24 is the answer
4 0
3 years ago
Read 2 more answers
Is anyone willing to help me with this? I tried adding this and still no answer. Please help..
GaryK [48]

Answer:   C. (-4, -2)

<u>Step-by-step explanation:</u>

First, eliminate one of the variables and solve for the remaining variable:

2x - 5y = 2      →    3(2x - 5y = 2)      →     6x - 15y = 6

3x + 2y = -16   →  -2(3x + 2y = -16)    →  <u> -6x - 4y = 32</u>

                                                                     -19y = 38

                                                                         y = -2


Next, replace "y" with -2 into either of the original equations to solve for x:

2x - 5y = 2

2x - 5(-2) = 2

2x + 10 = 2

2x         = -8

 x          = -4

                                       x = -4,  y = -2

<u>Check:</u>

Plug in the x- and y-values into the other original equation:

3x + 2y = -16

3(-4) + 2(-2) = -16

-12  +  -4     = -16

      -16         = -16   \checkmark

3 0
3 years ago
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