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Tems11 [23]
3 years ago
15

Help me answer number 9 PLEASEEEE

Mathematics
1 answer:
katrin [286]3 years ago
5 0
BD = BA + AD

51 = 26 + AD

-26 on both sides

AD = 25
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Find the volume of this object
Romashka-Z-Leto [24]

Answer:

423 cm^{3}

Step-by-step explanation:

V=3*3^{2} *14+\frac{3*3^{2}*5 }{3} =423cm^{3}

3 0
3 years ago
Need help urgently, please
Kaylis [27]
Answer: 26

There’s nothing here for me to solve
3 0
3 years ago
2
exis [7]
I believe it b I am sorry if iam wrong
7 0
3 years ago
Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0
3 years ago
There are 12 inches in a foot and 3 feet in a yard. If a baby step is 6 inches long. How many baby steps are needed to walk 3 ya
SashulF [63]
18 I believe. not 100%
8 0
3 years ago
Read 2 more answers
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