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Sonja [21]
3 years ago
13

What is the area? write your answers as a fraction or as a whole mixed number.

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

160/81

Step-by-step explanation:

Convert all the mixed fractions into improper fractions

Use the Area formula A=L x W

A = 16/9 x 10/9

A= 160/81 or 1 79/81

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The graph shows the amount of rainfall in a town in July over a
Rus_ich [418]

Answer:30%

Step-by-step explanation:

4 0
3 years ago
Find one value of xxx that is a solution to the equation: (5x+2)^2+15x+6=0(5x+2) 2 +15x+6=0
11111nata11111 [884]

An equation is formed of two equal expressions. The solution of the equation (5x+2)² + 15x + 6=0 is -0.4 and -1.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The solution to the equation,

(5x+2)² + 15x + 6=0

25x² + 4 + 20x + 15x + 6 = 0

25x² + 35x + 10 = 0

Plotting the equation on the graph, the value of x is,

x = -0.4, -1

Hence, the solution of the equation (5x+2)² + 15x + 6=0 is -0.4 and -1.

Learn more about Equation:

brainly.com/question/2263981

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5 0
2 years ago
Simplify the expression:<br> 4(2 + 5q) = 1
JulijaS [17]

Answer:

Step-by-step explanation:

4(2+5q) = 8 + 20q

8 + 20q = 1

20q = -7

q = -7/20

7 0
3 years ago
The graph shows the relationship between the number of pounds of pears purchase and the total cost of the pears.
Katarina [22]
The answer is $1.75 because that’s what the graph shows per pound of pears
6 0
3 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
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