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KATRIN_1 [288]
3 years ago
9

Can anyone help me about question 2

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

9514 1404 393

Answer:

  3(4/3)^2543

Step-by-step explanation:

Using logarithms base 2, we have ...

  (a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

  \log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}

and the 2544th term is ...

  \boxed{\log_2{a_{2544}}=3\left(\dfrac{4}{3}\right)^{2543}}

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