✅
Step-by-step explanation:


![\sqrt[3]{x + 1} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%20%3D%202)
Let us cube both sides.
![= > (\sqrt[3]{x + 1} ) ^{3} = {2}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%20%28%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%29%20%5E%7B3%7D%20%20%3D%20%20%7B2%7D%5E%7B3%7D%20)
Now, it will be only x + 1.

Transpose 1 to the Right Hand Side.

Now, subtract.

<u>Answer</u><u>:</u>
x = 7
Hope you could understand.
If you have any query, feel free to ask.
Answer:
The spruce tree had a faster groth rate.
Step-by-step explanation:
It maintained a constant rate and went from 6,5 to 8,6.
Answer:
2(3x-2(3x+2)
Step-by-step explanation:
1) 18x^2-8
2) 2(9x^2-4)
3) 2(3x-2)(3x+2)
I accept that θ in second quadrant, therefore sinθ > 0, cosθ < 0 and tanθ < 0.
