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Ludmilka [50]
2 years ago
5

A hot air balloon is at an elevation of 1,250 feet. Its elevation begins to change at a rate of -22.5 feet per minute. How many

minutes will it take the balloon to descend to an elevation of 935 feet? Use the Distance Formula: d = rt
Mathematics
1 answer:
Nataly_w [17]2 years ago
5 0

Let y represent the number of feet and x represent the number of minutes.  Convert 22 1/2 to decimal form: 22.5

 

y = -22.5x

 

Plug in -315 for y

 

-315 = -22.5x

 

divide both sides by -22.5

 

14 = x

 

It will take 14 minutes.

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one positive integer is 2 less than another. the product of the two integers is 24. what are the integers
erica [24]

Answer:

The integers are 4 and 6

Step-by-step explanation:

4 X 6 = 24

4 is two less than 6

4 0
3 years ago
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
50 POINTS
NeX [460]

Answer:

o I = 4 cm, w = 9 cm, h = 3 cm  

Step-by-step explanation:

The volume is given by V = l*w*h

w = 6 cm, I = 4,cm, h = 4 cm    V= 6*4*4 = 96

o w = 7 cm, h = 3 cm, I = 5 cm   V = 7*3*5 =105

o I = 4 cm, w = 9 cm, h = 3 cm   V = 4*9*3 =108

o h = 5 cm, w = 6 cm, I = 3 cm  V = 5*6*3 =90

The largest volume is

o I = 4 cm, w = 9 cm, h = 3 cm   V = 4*9*3 =108

8 0
2 years ago
Read 2 more answers
Classify the following triangle. Check all that apply
Alinara [238K]

Answer:

I think its B and E

Step-by-step explanation:

Hope it helps

8 0
2 years ago
Solve each equation for y (get into slope-intercept/y=mx + b form):
Gwar [14]

Answer:

Step-by-step explanation:

In order to do this we need to isolate y by performing the inverse operations on the other values like so...

a)   10x + 5y = 20   ... subtract 10x on both sides

     5y = 20 - 10x    ... divide both sides by 5

       y = 4 - 2x   ... we can move the 2x to the right to make it into y = mx + b

       y = -2x + 4

b)   3x - 2y = 10 + 4x   ... subtract 3x on both sides

      -2y = 10 + x    ... divide both sides by -2

       y = -5 - 0.5x ... move -0.5 to the left so it matches y = mx + b

      y = -0.5x - 5

3 0
3 years ago
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