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My name is Ann [436]
3 years ago
8

HELP ME PLEASE PLEASE PLEASE​

Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer:

  • #1)  3 different roots, total 6
  • #2) 3 different roots, total 9
  • #3) 3 different roots, total 4

Step-by-step explanation:

<h3>#1</h3>

<u>The roots are:</u>

  • x - 3 = 0 ⇒ x = 3, multiplicity 2
  • x + 1 = 0 ⇒ x = -1, multiplicity 3
  • 2x + 5 = 0 ⇒ x = -2.5
<h3>#2</h3>

<u>The roots are:</u>

  • x = 0, multiplicity 3
  • x + 2 = 0 ⇒ x = -2
  • x - 4 = 0 ⇒ x = 4, multiplicity 5
<h3>#3</h3>

<u>The roots are:</u>

  • x² - 1 = 0 ⇒ (x + 1)(x - 1) = 0 ⇒ x = -1, x = 1
  • x² + 4x + 4 = 0 ⇒ (x + 2)² = 0 ⇒ x + 2 = 0 ⇒ x = -1, multiplicity 2
Soloha48 [4]3 years ago
7 0

Answer:

1.16

2.14

3.13

Thank me later

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x=9 should be the answer

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3 years ago
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kozerog [31]
That’s the correct answer

3 0
4 years ago
8 less than 2 times a number is greater than the sum of the same number and 9
lyudmila [28]

step-by-step explanation:

every time we see "a number" or "the same number," we can add a variable (we'll use x here).  rewriting the problem, we get: 8 less than 2 times x is gr8er than the sum of  x and 9.  

next, we can work backwards to write an inequality.  we know from the word problem above that the number on the left side of the equation is 8 less than 2x, so we can rewrite that part like this: 2x-8.

for the right side of the equation, all we have to do is simplify "the sum of x and 9" to x + 9.  so now the inequality should look like this: 2x - 8 > x + 9.  

now we'll solve the inequality just like an equation: subtract x from both sides of the inequality, so now we have: x - 8 > 9.

then, we can add 8 to both sides to get the x by itself, and we get the answer: x > 15

hope this helps! <em>:)</em>

4 0
3 years ago
how do i answer this The school play includes 60 students. 3/5 of the students are actors. The rest of the students work behind
artcher [175]
1/5 equals 12 so 12 times 5 is 60 so
a=36
b=24
 Your welcome
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A 25-foot pole is supported by a 40-ft. guy wire that is anchored to the ground a certain distance away from the pole. What angl
IRISSAK [1]
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