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elena-s [515]
2 years ago
10

Would a phone, computer, and tablet work in space? Why?

Physics
2 answers:
vfiekz [6]2 years ago
8 0

Answer:

No

Explanation:

i dont think it would

ValentinkaMS [17]2 years ago
7 0

Answer:

"Satellites and space ships orbit at approximately 150 miles above the earth's surface. Given that a standard phone only works within a 10 miles radius of the tower, the satellite or spaceship would need its own tower. This tower would also need to be located on the outside of the space ship otherwise the metallic structure would block the signal. You would also need a dish antenna back on earth tracking the satellite to receive the signal."

-Techsling

This is a piece of text from an article so I advise that you do not copy and paste it or you might get in trouble.

So maybe it would but it would be extremely hard to do it.

Hope it helps bai!

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1.Explain frame of reference. How is it different when you are riding inside a car or standing by the highway?
galben [10]

Answer:

See explanation

Explanation:

A frame of reference simply refers to a set of coordinates which is used to determine the position and velocity of objects all the objects found in that particular frame. The person inside the car and standing by the highway are in different frames of reference.

Newtons first law of motion states that an object will continue to be at rest or in a state of uniform velocity until it is acted upon by an external force.

Newtons second law states that rate of change of momentum is directly proportional to the impressed force.

Newtons third law states that action and reaction are equal and opposite.

The action of applying brakes leads to an equal reaction of a sudden forward movement. Seat belts help to prevent the occupants of a car from being injured by the sudden stoppage of the car.

Force is simply defined as a push or pull.

Balanced forces do not lead to acceleration of a body but an unbalanced for leads to acceleration of a body.

strong nuclear force, electromagnetic force, weak nuclear force and gravity

Power is the rate of doing work while week is said to be done when the force applied moves a distance in the direction of the force. Power is defined as work/time.

8 0
3 years ago
What is the average velocity of a dragster that starts from rest at the starting line and finishes a race at 2600 m/s in 12 seco
xxMikexx [17]
Using the equation v(avg)=distance/time 
and the equation v=v(original)+a(t)
solve for acceleration
2600=0+a(12)
a=216.66666 m/s^2

Then, you use the equation
v^2=v(original)+2a*(change in x)
2600^2=2(216.666666)*change in x
6760000/2/216.666666 = 15600 meters which is the length of the race

Then using v(avg)=x/t
15600/12= 1300 m/s
7 0
3 years ago
If earth had no atmosphere, would a falling object ever reach terminal velocity?
stepan [7]
No, because terminal velocity is when the acceleration of the Earth’s gravity is balanced by the air resistance of the atmosphere.
5 0
3 years ago
The water flowing through a 2.0 cm (inside diameter) pipe flows out through three 1.3 cm pipes. (a) If the flow rates in the thr
Verdich [7]

Answer:

a)54L/min

b)0.845

Explanation:

a) A x V=A_1V_1+ A_2V_2+A_3V_3

where suffix 1,2,3 refers to the three pipes.

            =27L/min+16L/min+11 L/min

            =54L/min

b) A x V=54L/min => \frac{\pi }{4} d^2 x v

   d= 2 cm

\frac{\pi }{4} d^2 x v = 54

v= \frac{4}{\pi } x \frac{54}{2^2}

-> A_1 x V_1=27L/min => \frac{\pi }{4} d_1^2 x v_1

d_1= 1.3cm

\frac{\pi }{4} d^2 x v_1 = 27

v_1= \frac{4}{\pi } x \frac{27}{1.3^2}

Next is to find the ratio of speed i.e \frac{v}{v_1}

\frac{4}{\pi } x \frac{54}{2^2} / \frac{4}{\pi } x \frac{27}{1.3^2} => \frac{54}{27} \frac{1.3^2}{2^2}

\frac{v}{v_1}= 0.845

8 0
2 years ago
Any help would be great! Thank you x<br><br><br> Giving brainliest answer xoxo
garri49 [273]

Answer:

A vacuum would have been created. I hope this helps have a great day

3 0
3 years ago
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