To start with solving this
problem, let us assume a launch angle of 45 degrees since that gives out the
maximum range for given initial speed. Also assuming that it was launched at
ground level since no initial height was given. Using g = 9.8 m/s^2, the
initial velocity is calculated using the formula:
(v sinθ)^2 = (v0 sinθ)^2
– 2 g d
where v is final
velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m
Rearranging to find for
v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>
<span>v0 = 10.383 m/s</span>
-- The net vertical force on the object is zero.
Otherwise it would be accelerating up or down.
-- The net horizontal force on the object is zero.
Otherwise it would be accelerating horizontally,
that is, its 'velocity' would not be constant. That
would contradict information given in the question.
The total net force on the object is the resultant of the
net vertical component and net horizontal component.
Total net force = √(0² + 0²)
= √(0 + 0)
= √0
= Zero.
The correct answer is the last choice on the list.
Also, you know what ! ? It doesn't even matter whether the surface it's
sliding on is frictionless or not.
If the object's velocity is constant, then the NET force on it must be zero.
If it's sliding on sandpaper, then something must be pushing it with constant
force, to balance the friction force, and make the net force zero. If the total
net force isn't zero, then the object would have to be accelerating ... either
its speed, or its direction, or both, would have to be changing.
Answer:
Explanation:
Charge on an electron (q) = 1.6 * 10 ^ -19 C
Velocity of electron (v) = 0.3037 * 300,000,000 = 91,110,000 m/sec
We know that, Force exerted on moving particle moving through a magnetic field :
1.2498 * 10 ^ -12 = 1.6 * 10^ -19 * 91110000 * B
B = 0.08573 T
Answer:
W = 8.01 × 10^(-17) [J]
Explanation:
To solve this problem we need to know the electron is a subatomic particle with a negative elementary electrical charge (-1,602 × 10-19 C), The expression to calculate the work is given by:
W = q*V
where:
q = charge = 1,602 × 10^(-19) [C]
V = voltage = 500 [V]
W = work [J]
W = 1,602 × 10^(-19) * 500
W = 8.01 × 10^(-17) [J]
Answer:
5.61 seconds
Explanation:
The baseball moves as a projectile. Its angle is 45° and its velocity is 95 miles per hour.
Let us convert this to metres per second:
1 mile per hour = 0.45 m/s
95 miles per hour = 95 * 0.45 = 42.75 m/s
We need to find the time of flight of the baseball. Time of flight is given as:
where u = initial velocity
α = angle
g = acceleration due to gravity (9.8 m/s)
Therefore:
The baseball was in the air for 5.61 seconds.
