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solong [7]
3 years ago
5

Jimmy walks to school by traveling 2.0 miles east and 3.0 miles north from his starting point. What are the magnitude and direct

ion of Jimmy's displacement with respect to his original position?
Physics
1 answer:
DIA [1.3K]3 years ago
4 0

Answer:

3.6 miles at 56.3 degrees north of east.

Explanation:

If you draw a diagram to calculate Jimmy's displacement, you end up with a triangle.

To solve for the magnitude of Jimmy's displacement with respect to his original position, we need to use the <u>Pythagorean Theorem</u> formula.

Pythagorean Theorem Formula = a^2 + b^2 = c^2

Step by Step to solve for the magnitude of Jimmy's displacement:

1) a^2 + b^2 = c^2

2) 2.0^2 + 3^2 = c^2

3) 4 + 9 = c^2

4) 13 = c^2

5) To find what "c" equals to we need to find the square root of 13.

6) √13 = 3.6 | c = 3.6 miles

To solve for the direction of Jimmy's displacement with respect to his original position, we need to use the following formula:

tan^-1 ∅ (3/2)

tan^-1 ∅ (1.5)

∅ = 56.309° north of east

Therefore, your answer is 3.6 miles at 56.3 degrees north of east.

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Well,

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Why do we use other bonding theories in addition to the lewis model?
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Full Question:

Why do we use other bonding theories in addition to the lewis model?

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Answer:

b) Lewis model cannot predict all of the properties of a molecule or ion.

Explanation:

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8 0
4 years ago
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Answer:

F<em>lift=</em>5.00×10³ N

F<em>horizontal</em>=0.50×10³ N

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Explanation:

A free-body diagram of the glider.

pretend this is a number line

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∨

hope this helps! :)

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