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2 years ago

What is 50 + 0 x 20 + 10?

Mathematics

1 answer:

Temka [501]2 years ago

8 0

$50 + 0 \times 20 + 10 \\ 50 + 0 + 10 \\ = 60$

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P varies directly with the square of R. When R is 4, P is 56. Find the value of P when R is 6

Sav [38]

Hey!
The formula of direct variation is y = kx. So we know that p = kr^2
Hint: after it says varies, it's basically the equal sign.
so we can set it up
56 = 4^2k
56=16k
now we want k alone so we have to divide 16 on both sides
k=3.5
We can now solve for p like it asks
p = 3.5*6^2
p=126
There's your answer!
Hope this helps!

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2 years ago

The temperature of a freezer started at 18ºC. After cooling for a few hours, the freezer had a temperature of –12ºC. What is the

Zarrin [17]

Answer:

a.–12 – 18

Step-by-step explanation:

We have to compute the difference (the subtraction) between the new, colder temperature, which is equal to -12 °C, and the original temperature, which is equal to 18 °C, that is:

colder temperature - original temperature

Replacing with data:

-12 °C - 18 °C = -30 °C

5 0

3 years ago

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Dylan wants to buy both the tablet and

nignag [31]

Answer:

108$

Step-by-step explanation:

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2 years ago

The oblique pyramid has a square base. What is the volume of the pyramid? 2.5 cm3 5 cm3 6 cm3 7.5 cm3

Olenka [21]

Take a look at the attachment below. It fills in for the attachment that wasn't provided in the question -

An oblique pyramid is one that has a top not aligned with the base. Due to this, the height of the pyramid connects with two vertices at its ends to form a right angle present outside the pyramid, knowing that it is always perpendicular to the base. There is no difference between the calculations of the volume of an oblique pyramid and a pyramid however -

$\\Base Area = 2 cm * 2 cm = 4 cm^2,\\Volume ( Pyramid ) = 1 / 3 * ( Base Area ) * ( Height ),\\Volume = 1 / 3 * ( 4 ) * ( 3.75 ),\\-------------------------\\Volume = 5 cm^3$

And thus, you're solution is 5 cm^3, or in other words option b!

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2 years ago

Solving fp Algebra 2 I do not understand how to solve this, could someone please explain?

Olenka [21]

$f(x) = \sqrt{x + 2}$
What's The Fixed Point? Well, Let's Assume X=0, this is our point.

$f(0) = \sqrt{0 + 2} \\ f(0) = \sqrt{2} \\ this \: is \: our \: fixed \: point \: \\ (0, \sqrt{2} )$
OR

$f(p) = \sqrt{p + 2} \\ \\ or \: \sqrt{x + 2} = 0 \\ ( \sqrt{x + 2} ) ^{2} = {0}^{2} \\ x + 2 = 0 \\ x = - 2$
I'm unaware of the nature of the question, so here are some different ways a fixed point is found based on the merits of the question.

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2 years ago