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3 years ago

How to find the value of x

Mathematics

1 answer:

Marta_Voda [28]3 years ago

6 0

Well to find it add the numbers up because all together they equal 540 degrees then subtract 540 to the number it add up to.

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What is the slope of the line that passes through the points (3, -2) and (9, -2)?

ICE Princess25 [194]

m=(-2+2)/(9-6)=0/3=0

m=0

7 0

2 years ago

What does 351 = (y × 8) + 7 equal

bogdanovich [222]

Simplify brackets

351 = y * 8 + 7

Regroup terms

351 = 8y + 7

Subtract 7 from both sides

351 - 7 = 8y

Simplify 351 - 7 to 344

344 = 8y

Divide both sides by 8

344/8 = y

Simplify 344/8 to 43

43 = y

Switch sides

6 0

3 years ago

Read 3 more answers

What are line segments?

laiz [17]

Answer:

In geometry, a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line between its endpoints. A closed line segment includes both endpoints, while an open line segment excludes both endpoints; a half-open line segment includes exactly one of the endpoints

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.