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Kamila [148]
3 years ago
14

How to find the value of x

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0
Well to find it add the numbers up because all together they equal 540 degrees then subtract 540 to the number it add up to.
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Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d
Free_Kalibri [48]

The intersection of sets R and D is give by the following set:

R ∩ D = {3, 9, 15}.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.

<h3>What is the set that is the intersection of two sets?</h3>

The set that is the intersection of two sets is composed by the elements that belong to both sets.

For this problem, the sets are given as follows:

  • R = {1,3,5,7,9,11,13,15,17}.
  • D={3,6,9,12,15,18,21,24,27}

Hence the intersection is given by:

R ∩ D = {3, 9, 15}.

As the elements 3, 9 and 15 are the only ones that belong to both sets.

More can be learned about intersection of sets at brainly.com/question/11439924

#SPJ1

3 0
1 year ago
Construct a triangle STU in which<br>LT=60o Lu=70° and TU = 7.5 cm<br>60°​
disa [49]
Ok first you have to multiply and get scammed
6 0
3 years ago
What is the radical and simplest form of 16 5/4
Inga [223]

Answer:

17 1/4 or 69/4

Step-by-step explanation:

Hope it helped

3 0
3 years ago
What is the value of the expression |a + b| + |c| when a = –5, b = 8, and c = –13?
nasty-shy [4]
|a+b| + |c| when a= -5, b= 8, c= -13:

|-5+ 8|+ |-13|
= |3|+ 13
= 3+ 13
= 16

The correct answer is D. 16~
7 0
3 years ago
2x + 19 and x + 23 are alternate exterior angles. What is the value of x? *
Mamont248 [21]

Answer:

4

Step-by-step explanation:

2x+19=x+23

We simplify the equation to the form, which is simple to understand

2x+19=x+23

We move all terms containing x to the left and all other terms to the right.

+2x-1x=+23-19

We simplify the left and right sides of the equation.

+1x=+4

We divide both sides of the equation by 1 to get x.

x=4

5 0
2 years ago
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