The slope of line D is also -4 because the lines are perpendicular.
Answer:
![x=2+\frac{1}{2}\sqrt[]{21}](https://tex.z-dn.net/?f=x%3D2%2B%5Cfrac%7B1%7D%7B2%7D%5Csqrt%5B%5D%7B21%7D)
or
Step-by-step explanation:
Add 21 on both sides.
a=4
b=-16
c=-5
![x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%20%20%7D%7B2a%7D)
![x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)} }{2(4)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-16%29%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B%28-16%29%5E2-4%284%29%28-5%29%7D%20%20%7D%7B2%284%29%7D)
![x=\frac{16\frac{+}{}\sqrt[]{256+80} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B256%2B80%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}\sqrt[]{336} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B336%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D%5Csqrt%5B%5D%7B2%5E2%2A2%5E2%2A21%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}2*2\sqrt[]{21} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D2%2A2%5Csqrt%5B%5D%7B21%7D%20%20%7D%7B8%7D)
![x=\frac{16\frac{+}{}4\sqrt[]{21} }{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%5Cfrac%7B%2B%7D%7B%7D4%5Csqrt%5B%5D%7B21%7D%20%20%7D%7B8%7D)
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![x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%7D%7B8%7D%2B%5Cfrac%7B4%5Csqrt%5B%5D%7B21%7D%7D%7B8%7D)
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![x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B16%7D%7B8%7D-%5Cfrac%7B4%5Csqrt%5B%5D%7B21%7D%7D%7B8%7D%5C%5Cx%3D2-%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B%7B21%7D)
Equation- p-6= -14
Answer- p=-14
Common ratio can be found by dividing the 2nd term by the first
r = 48/6
r = 8
an = a1 * r^(n-1)
n = term to find = 8
a1 = first number = 6
r = common ratio = 8
now we sub
a(8) = 6 * 8^(8-1)
a(8) = 6 * 8^7
a(8) = 6 * 2097152
a(8) = 12582912 <==
Answer:
5(1248 lb/horse + t lb) ≤ 8000 lb
Step-by-step explanation:
One way to do this is to find the average weight of the 5 horses:
It is:
6,240 lb
---------------- = 1248 lb/horse
5 horses
and to this, for each horse, we must add t lbs tack.
Thus, 5(1248 lb/horse + t lb) ≤ 8000 lb
would be an appropriate inequality.
Please note that your question mentions "the following inequalities;" that means you are expected to share them! Please do so next time. Thanks.
