Answer:
75°
Step-by-step explanation:
1. Consider right triangle ABC. In this triangle
m∠C = 90º and CM - angle bisector.
If CM is angle C bisector, then
m∠ACM = m∠MCB = 45º
2. Consider triangle CMB. The sum of the measures of all interior angles of the triangle is always 180°, then
m∠MCB + m∠CBM + m∠BMC = 180°,
m∠BMC = 180° - 45° - 30°
m∠BMC = 105°
3. Angles AMC and BMC are supplementary angles, so
m∠AMC + m∠BMC = 180°
m∠AMC = 180° - 105°
m∠AMC = 75°
Answer:
the question is about the table you have to make a table it is very easy
Answer:
c would be the correct answer
Step-by-step explanation:
It should be two if this is pre calc.
Distribute
4x(2x^2-4x+5)-5x(2x+6)
8x^3-16x^2+20x-10x^3-30x
Combine Like Terms
8x^3-16x^2+20x-10x^3-30x
-2x^3-16^2+20x-30x
Combine like terms
-2x^3-16x^2 +20x-30x
-2x^3-16x^2-10x
Common factor
Factor by grouping
-2x^3 - 16x^2-10x
Find one factor
-2(x^3+8x^2+5x)
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<h2>Your answer: -2x(5x^2+4x+5)</h2><h2>(Simplified = 10x^3 + 8x^2 + 10x)</h2>
