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zmey [24]
3 years ago
11

PLEASE HELP 25 POINTS

Mathematics
1 answer:
Elza [17]3 years ago
3 0

Answer:

<em>h</em><em>,</em><em>ozhnvj</em><em> </em><em>jzojIcjcjzmZncnxkx</em>

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Solve the equation 11-p=19
Aloiza [94]
You subtract 11 from 19 and then the answer is 8
3 0
3 years ago
A rock is thrown upward from a bridge that is 57 feet above a road. The rock reaches its maximum height above the road 0.76 seco
bekas [8.4K]

answer:

f(t) = -9.9788169(t -0.76)^2 +57

Step-by-step explanation:

On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the  number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).

now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is f(x)= a(x-p)^2 +q  , where (p,q) is the turning point. now we substitute the turning point

f(t) = a(t-0.76)^2 + 57, now we will substitute the other point on the graph or on the function that we found which is (3.15, 0) then solve for a.

0 = a(3.15 - 0.76)^2 + 57

-57 =a(2.39)^2  

-57 = a(5.7121)

-57/5.7121 =a

-9.9788169 = a      then we substitute a to get the quadratic equation therefore f is

f(t) = -9.9788169(t-0.76)^2 +57

4 0
2 years ago
1. The US Mint has a specification that pennies have a mean weight of 2.5g. From a sample of 37 pennies, the mean weight is foun
Evgesh-ka [11]

Answer:

the pennies does not conform to the US mints specification

Step-by-step explanation:

z = (variate -mean)/ standard deviation

z= 2.5 - 2.4991 / 0.01648 = 0.0546

we are going to check the value of z in the normal distribution table, which is the table bounded by z.

checking for z= 0.0 under 55 gives 0.0219 (value gotten from the table of normal distribution)

we subtract the value of z from 0.5 (1- (0.5+0.0219)) = 0.4781 > 0.05claim

since 0.4781 > 0.05claim, therefore, the pennies does not conform to the US mints specification

the claim state a 5% significance level whereas the calculated significance level is 47.81%. therefore, the claim should be rejected

7 0
3 years ago
1 pt) find the average rate of change of the function over the given intervals. h(t)=\cot (t);
blondinia [14]

\text{Consider the function}\\&#10;\\&#10;h(t)=\cot(t) \text{ on the interval }\left [ \frac{\pi}{4}, \ \frac{3\pi}{4} \right ]\\&#10;\\&#10;\text{we know that the average rate of change of a funtion f(x) over the }\\&#10;\text{interval [a, b] is given by}\\&#10;\\&#10;f_{avg}=\frac{f(b)-f(a)}{b-a}\\&#10;\\&#10;\text{so using this, the average rate of change of the given function is}

h_{avg}=\frac{h\left ( \frac{3\pi}{4} \right )-h\left ( \frac{\pi}{4} \right )}{\frac{3\pi}{4}-\frac{\pi}{4}}\\&#10;\\&#10;=\frac{\cot \left ( \frac{3\pi}{4} \right )-\cot \left ( \frac{\pi}{4} \right )}{\frac{3\pi-\pi}{4}}\\&#10;\\&#10;=\frac{(-1)-(1)}{\frac{2\pi}{4}}\\&#10;\\&#10;=\frac{-2}{\frac{\pi}{2}}\\&#10;\\&#10;\text{Average rate of change of function}=\frac{-4}{\pi}

6 0
3 years ago
HELPP YALL! I WILL MARK BRAINIEST!! LOOK AT THE PICTURE!!
UNO [17]

Answer:

So we know the total is 34

B to C will be 15 so that's around half the total

So let's subtract the given part from the total

34 = 15 = 19

AB = 19

4 0
3 years ago
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