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3 years ago

6

What is the slope of a line that passes through the points ( 3,7) and(12,7)?

2 answers:

Minchanka [31]3 years ago

7 0

Answer:

The slope is 0.

Step-by-step explanation:

To find the slope, we can do (7 - 7) / (12 - 3) = 0 / 9 = 0. This makes sense because if we look at the points, they both have the same y-coordinate, so we know that as x increases / decreases, y never changes. Because y never changes, the slope is 0.

sergey [27]3 years ago

6 0

Answer:

m=0

Step-by-step explanation:

To find slope, it is y2-y1/x2-x1

Therefore, x1=3, x2=12, y1=7 and y2=8

Plugging those variables in,

(7-7)/(12-3)=

7-7=0

12-3=9

0/9=0

Therefore, slope of the line that passes through points (3,7) and (12,7) is 0

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

$m_ {1} * m_ {2} = - 1$

The given line is:

$5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3$

So we have:

$m_ {1} = \frac {5} {2}$

We find $m_ {2}:$ $m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}$

So, a line perpendicular to the one given is of the form:

$y = - \frac {2} {5} x + b$

We substitute the given point to find "b":

$-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2$

Finally we have:

$y = - \frac {2} {5} x-2$

In point-slope form we have:

$y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)$

ANswer:

$y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)$

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