Answer:
answer is B
Step-by-step explanation:
Answer:
sample variance
the value of the one observation
the mean value of all observations
the number of observations
Step-by-step explanation:
Since there are two black queens out of 52 cards, there is a 2/52 chance of drawing a black queen first. This is equivalent to a 1/26 chance.
Now that we have removed a black queen, there are 51 cards left in the deck. 26 of them are red because we only took away a black card. This means that there is a 26/51 of drawing a red card next.
In order to find the probability of both of these happening, we multiply the two together. 1/26 * 26/51 = 26/1326. This reduces to 1/51. So, there is a 1/51 chance of drawing a black queen, then a red card.
Answer:
Yes.
Step-by-step explanation:
If a graph G doesn't have a circuit, we must have that
![|E(G)|=|V(G)|-1](https://tex.z-dn.net/?f=%7CE%28G%29%7C%3D%7CV%28G%29%7C-1)
where
is the number of edges of the graph and
the number of vertices. However, in this case it holds that
![|E(G)|=72>68=|V(G)|.](https://tex.z-dn.net/?f=%7CE%28G%29%7C%3D72%3E68%3D%7CV%28G%29%7C.)
Your answer will most likely be D. h > 42 and h must be a positive number. Reasoning: H has to be greater than 42 to ride the ride, and it cannot be a negative number because H has to be greater than 42 and if you make it negative, it will be less than 42