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2 years ago

Please help!!!!!!!!!!

Mathematics

1 answer:

lesya [120]2 years ago

4 0

Answer:

Step-by-step explanation:

look at m a t h w a y

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A team of biologists captured and tagged 65 deer in a forest. Two weeks later, the

Gre4nikov [31]

Answer:

1/6x= 65

Step-by-step explanation:

so we can assume that 5/10= 1/6 of the deer were tagged

lets call the total number of dear x

so 1/6x= 65

x= 380

4 0

3 years ago

Tickets to Disney World are $100..The price is going to increase on January ,What is the cost percentage of change if the cost i

bearhunter [10]

Answer:

I am not so sure but if I were to choose it went up from an 200% increase.

Step-by-step explanation:

8 0

2 years ago

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

2 years ago

Expand the binomial (a+2)^4

dimaraw [331]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Spanish class has a total of 30 students. The number of males is 12 more than the number of females. How many males and how many

docker41 [41]

Answer:

21, 9

Step-by-step explanation:

If girls are x, then boys are x + 12

x + x + 12 = 30

2x + 12 = 30

2x = 18

x = 9

There are 9 girls and 21 boys

8 0

1 year ago

Read 2 more answers