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mafiozo [28]
3 years ago
7

If sin x = 12÷13 where 0° <x<90°find the value of 1-cos ×cos( x)​

Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

This is how tackle this type of problem:

Draw a right triangle with the indicated sides: side opposite the angle = 12 and hypotenuse = 13

Then, calculate the 3rd side by Pythagoras: x2 + 122 = 132

x2 = 169 - 144

x2 = 25

x = 5

Now, we have all 3 sides of our diagram triangle, so we can find all the trig ratios for the angle.

Next, we use the double angle formula to simplify cos(x + 30) = cos x cos 30 - sin x sin 30

= 5/13 . √3/2 - 12/13 . 1/2

= 5√3 /26 - 6/13

= (5√3 - 12) / 26

Step-by-step explanation:

please mark me as brainlist please hi

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