Answer:
The initial height is the y-intercept of the graph
slope of the graph = -2
Jordon interprets the only the slope correctly.
Aral interprets the only the initial height correctly.
Step-by-step explanation:
Slope = change in y ÷ change in x = (0 - 12) ÷ (6 - 0) = -12 ÷ 6 = -2
So the slope of the graph = -2
by inspection, the y-intercept = 12
Therefore, the equation for the line is y = -2x + 12
Jordon interprets the only the slope correctly.
Aral interprets the only the initial height correctly
We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:
![CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack%20x-Z_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%2Cx%2BZ_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%5Crbrack)
Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:
![CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack30.0-Z_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%2C30.0%2BZ_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%5Crbrack)
Where (from tables):

Finally, the interval at 98% confidence level is:
V = πr²h
V = (3.14)(5)²(16)
V = (3.14)(25)(16)
V = 1256
Hope this helps :)
Answer:
<h2>x = 4.8</h2>
Step-by-step explanation:

Answer:
Step-by-step explanation:
The slope is going to be the one that has the X by it so your slope is going to be 5x. Then your y intercept is going to be the number behind the slope so the y intercept is positive 1.