F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
Answer:
12.566368 units
Step-by-step explanation:
2(pi)r = C
2(pi)(2) = C
4(pi) = C
4(3.141592) = C
12.566368 = C
Yes, it should be taken into account
9514 1404 393
Answer:
zero solutions
Step-by-step explanation:
The first inequality has a boundary line with a slope of 3 and a y-intercept of 9. Shading is above the boundary line.
The second inequality has a parallel boundary line with a slope of 3 and a y-intercept somewhat lower, at -1. Shading is below this boundary line.
There is a gap between the shaded areas, so no points will be solutions to both inequalities.
Answer:
3
Step-by-step explanation:
Given that:
The number of paint sets, Suzanne bought= 6
As each set contains the same number of brushes.
Let x be the number of brushes each set contains.
So, the total number of brushes in 6 sets = 6x.
It is given that the total number of brushes she has is 18, which is equals to 6x.
So, the required equation is



Hence, the number of paint brushes each set contains is 3.