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natali 33 [55]
3 years ago
15

Graph Data ALG 2 Please Help!

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

1.  Figure 3

2. 2881.4 cm³

Step-by-step explanation:

The graph in figure 3 has a curve that fits the data best because it captures most of the points unlike the other two curves.

The curve in figure 3 has the equation;

y=-16.9x^2 +430x+523

2.

When using x=8, substitute the value of x in the equation with 8 to get

y = -16.9*64 + 430*8 + 523

y= 2881.4

= 2881.4 cm³

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Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
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Answer:

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b) 2.99

c) 2.99

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Part a)

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In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

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Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

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