6 miles in 2 hours how fast you go
2 answers:
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Answer:
The sample has not met the required specification.
Step-by-step explanation:
As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow
: The true average penetration is 50 mils
: The true average penetration is > 50 mils
Since we are trying to see if the true average is greater than 50, this is a right-tailed test.
If the <em>level of confidence</em> is α = 0.05 then the score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)
The z-score associated with this test is
where
= <em>mean of the sample</em>
= <em>average established by the specification</em>
s = <em>standard deviation of the sample</em>
n = <em>size of the sample</em>
Computing this value of z we get z = 3.42
Since z > we can conclude that the sample has not met the required specification.
Answer:
Step-by-step explanation:
a ) The worth of Jean-Claude's gnome after 1 year
= 80000 x 1.02
= £81600
b ) common ratio of geometric progression
= 81600 / 80000
= 1.02
c ) worth after 10 years
= 80000 x 1.02¹⁰
= 80000 x 1.21899
= £97519.55
d )
120000 = 80000 x
1.5 =
ln1.5 = k ln 1.02
k = ln 1.5 / ln 1.02
= .4054 / .0198
= 20.47 years .