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Tasya [4]
3 years ago
7

Mandy has a 10.2-ounce container of mustard. She uses 130 of the mustard to put on her hot dog each time. How many ounces of mus

tard are left after she has eaten 6 hot dogs?
Mathematics
1 answer:
geniusboy [140]3 years ago
8 0

Answer: it is 10 over 100

Step-by-step explanation:

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What is the real part of 4 - 5i
tensa zangetsu [6.8K]

Answer:

 5i is an imaginary number

7 0
3 years ago
HELP PLS
olchik [2.2K]

3996  \times  \frac{1}{3}  = 1332
the volume is 1332 in^3


good luck
4 0
3 years ago
En una sociedad participan 5 socios, colocando todos capitales iguales, lo unico que el primer socio estuvo 1 año y medio, el se
Mashutka [201]

Answer:

Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

Step-by-step explanation:

Dado que en una sociedad participan 5 socios, colocando todos capitales iguales, lo único que el primer socio estuvo 1 año y medio, el segundo 9 meses, el tercero 5 meses mas que el primero, el cuarto 1 año 7 meses y el quinto 2 años, para determinar cuánto le toca a cada socio de una utilidad de Q. 55,230.00 se deben realizar los siguientes cálculos:

Socio 1 = 1.5 años

Socio 2 = 0.75 años

Socio 3 = 1.916 años

Socio 4 = 1.583 años

Socio 5 = 2 años

Total = 1.5 + 0.75 + 1.916 + 1.583 + 2 = 7.75

Socio 1 =

7.75 = 100

1.50 = X

1.50 x 100 / 7.75 = X

19.35 = X

55,230 x 0.1935 = 10,690

Socio 2 =

7.75 = 100

0.75 = X

0.75 x 100 / 7.75 = X

9.68 = X

55,230 x 0.0968 = 5,345

Socio 3 =

7.75 = 100

1.916 = X

1.916 x 100 / 7.75 = X

24.72 = X

55,230 x 0.2472 = 13,655

Socio 4 =

7.75 = 100

1.583 = X

1.583 x 100 / 7.75 = X

20.43 = X

55,230 x 0.2043 = 11,285

Socio 5 =

7.75 = 100

2 = X

2 x 100 / 7.75 = X

25.81 = X

55,230 x 0.2581 = 14,255

Por lo tanto, Socio 1 recibirá Q. 10,690, Socio 2 recibirá Q. 5,345, Socio 3 recibirá Q. 13,655, Socio 4 recibirá Q. 11,285 y Socio 5 recibirá Q. 14,255.

5 0
2 years ago
Use (<,>,=) to compare 2/3 and 3/4
lina2011 [118]
2/3 < 3/4. Hope that helps
3 0
3 years ago
The universal set in this diagram is the set of integers from 1 to 15. place the integers in the correct place in the venn diagr
neonofarm [45]

Answer:


Step-by-step explanation:

Given :  universal set in this diagram is the set of integers from 1 to 15.

Solution :

The intersection of odd integer,multiples of 3 and Factors of 15 are 3,15

The intersection of odd integer and Factors of 15 are 1,5

The intersection of odd integer,multiples of 3 is 9

The remaining multiples of 3 are 6,12

The remaining odd integers are 7,11,13

Now the remaining integers are 2,4,8,10,14 and these integers must be placed in the boxes outside the circles Since they does not belong any intersection or odd integer or factor of 15 .

Refer the attached figure for the answer.

3 0
3 years ago
Read 2 more answers
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